OCR PURE — Question 11 4 marks

Exam BoardOCR
ModulePURE
Marks4
PaperDownload PDF ↗
TopicDiscrete Probability Distributions
TypeProbability distribution from formula
DifficultyChallenging +1.2 Part (a) is routine substitution into a given formula. Part (b) requires systematic enumeration of cases where X₃ > X₁ + X₂, calculating probabilities for each outcome combination - this involves careful organization and multiple probability calculations but uses standard techniques without requiring novel insight. The computational demand and case-work elevate it slightly above average difficulty.
Spec2.04a Discrete probability distributions

11 In this question you must show detailed reasoning. A biased four-sided spinner has edges numbered \(1,2,3,4\). When the spinner is spun, the probability that it will land on the edge numbered \(X\) is given by \(P ( X = x ) = \begin{cases} \frac { 1 } { 2 } - \frac { 1 } { 10 } x & x = 1,2,3,4 , \\ 0 & \text { otherwise } . \end{cases}\)
  1. Draw a table showing the probability distribution of \(X\). The spinner is spun three times and the value of \(X\) is noted each time.
  2. Find the probability that the third value of \(X\) is greater than the sum of the first two values of \(X\).

Question 11(a):
\(1 \quad 2 \quad 3 \quad 4\)
AnswerMarks Guidance
\(\frac{2}{5} \quad \frac{3}{10} \quad \frac{1}{5} \quad \frac{1}{10}\) oeB1 (1.1) B1
Question 11(b):
DR: \(1,1,3\); \(1,1,4\); \(1,2,4\); \(2,1,4\)
AnswerMarks Guidance
\(\left(\frac{2}{5}\right)^2\times\frac{1}{5} + \left(\frac{2}{5}\right)^2\times\frac{1}{10} + \frac{2}{5}\times\frac{3}{10}\times\frac{1}{10} + \frac{3}{10}\times\frac{2}{5}\times\frac{1}{10}\)B1 (3.1a) B1 for any three of these soi, e.g. on tree diagram
M1 (2.1)Any two correct products added: ft their table
\(= \frac{9}{125}\) or \(0.072\)A1 (1.1)
# Question 11(a):

$1 \quad 2 \quad 3 \quad 4$
$\frac{2}{5} \quad \frac{3}{10} \quad \frac{1}{5} \quad \frac{1}{10}$ oe | B1 (1.1) | B1

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# Question 11(b):

DR: $1,1,3$; $1,1,4$; $1,2,4$; $2,1,4$

$\left(\frac{2}{5}\right)^2\times\frac{1}{5} + \left(\frac{2}{5}\right)^2\times\frac{1}{10} + \frac{2}{5}\times\frac{3}{10}\times\frac{1}{10} + \frac{3}{10}\times\frac{2}{5}\times\frac{1}{10}$ | B1 (3.1a) | B1 for any three of these soi, e.g. on tree diagram

| M1 (2.1) | Any two correct products added: ft their table

$= \frac{9}{125}$ or $0.072$ | A1 (1.1) |
11 In this question you must show detailed reasoning.
A biased four-sided spinner has edges numbered $1,2,3,4$. When the spinner is spun, the probability that it will land on the edge numbered $X$ is given by\\
$P ( X = x ) = \begin{cases} \frac { 1 } { 2 } - \frac { 1 } { 10 } x & x = 1,2,3,4 , \\ 0 & \text { otherwise } . \end{cases}$
\begin{enumerate}[label=(\alph*)]
\item Draw a table showing the probability distribution of $X$.

The spinner is spun three times and the value of $X$ is noted each time.
\item Find the probability that the third value of $X$ is greater than the sum of the first two values of $X$.
\end{enumerate}

\hfill \mbox{\textit{OCR PURE  Q11 [4]}}