Edexcel FM2 AS 2021 June — Question 4 11 marks

Exam BoardEdexcel
ModuleFM2 AS (Further Mechanics 2 AS)
Year2021
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable acceleration (1D)
TypeDisplacement from velocity by integration
DifficultyStandard +0.8 This is a Further Maths mechanics question requiring integration of trigonometric velocity to find displacement, analysis of motion bounds, and calculating time intervals. While the integration itself is standard (∫sin 2t dt), parts (b) and (c) require understanding of periodic motion, finding extrema, and careful analysis of when x > 3 over multiple periods. The multi-step reasoning and periodic motion analysis elevate this above routine A-level questions but it remains a structured textbook-style problem.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.08a Fundamental theorem of calculus: integration as reverse of differentiation1.08d Evaluate definite integrals: between limits3.02a Kinematics language: position, displacement, velocity, acceleration3.02b Kinematic graphs: displacement-time and velocity-time3.02c Interpret kinematic graphs: gradient and area3.02f Non-uniform acceleration: using differentiation and integration

  1. A particle \(P\) moves on the \(x\)-axis. At time \(t\) seconds, \(t \geqslant 0 , P\) is \(x\) metres from the origin \(O\) and moving with velocity \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) in the direction of \(x\) increasing, where
$$v = 5 \sin 2 t$$ When \(t = 0 , x = 1\) and \(P\) is at rest.
  1. Find the magnitude and direction of the acceleration of \(P\) at the instant when \(P\) is next at rest.
  2. Show that \(1 \leqslant x \leqslant 6\)
  3. Find the total time, in the first \(4 \pi\) seconds of the motion, for which \(P\) is more than 3 metres from \(O\)
    \includegraphics[max width=\textwidth, alt={}]{a7901165-1679-4d30-9444-0c27020e32ea-16_2260_52_309_1982}

Question 4(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Instantaneous rest: \(v = 5\sin 2t = 0\)M1 Solve \(v = 0\) to find the first value of \(t > 0\)
\(\Rightarrow t = \frac{\pi}{2}\)A1 Or equivalent (accept \(2t = \pi\))
Differentiate to obtain \(a\): \(a = 10\cos 2t\ (= 10\cos\pi = -10)\)M1 Use \(a = \frac{\mathrm{d}v}{\mathrm{d}t}\) and substitute for \(t\)
\(10\ (\text{ms}^{-2})\) towards \(O\)A1 Correct only
Question 4(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Integrate to obtain \(x\): \(x = -\frac{5}{2}\cos 2t\ (+C)\)M1 Use \(x = \int v\,\mathrm{d}t\). Condone missing \(+C\)
Use boundary conditions: \(t = 0,\ x = 1 \Rightarrow C = \frac{7}{2}\)M1 Use boundary conditions to find \(C\)
\(x = \frac{7}{2} - \frac{5}{2}\cos 2t\)A1 Any equivalent form
\(-1 \leq \cos 2t \leq 1 \Rightarrow 1 \leq x \leq 6\)A1* Deduce given answer from correct working
Question 4(c):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(x = \frac{7}{2} - \frac{5}{2}\cos 2t = 3 \Rightarrow \cos 2t = \frac{1}{5},\ t = 0.6847...\)M1 Use trig to find a relevant value of \(t\)
Total time \(= 4\pi - 8t\)M1 Correct method for the total time
\(= 7.1\ \text{(s)}\) or betterA1 \(7.1\ \text{(s)}\) or better \(7.08861...\)
## Question 4(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Instantaneous rest: $v = 5\sin 2t = 0$ | M1 | Solve $v = 0$ to find the first value of $t > 0$ |
| $\Rightarrow t = \frac{\pi}{2}$ | A1 | Or equivalent (accept $2t = \pi$) |
| Differentiate to obtain $a$: $a = 10\cos 2t\ (= 10\cos\pi = -10)$ | M1 | Use $a = \frac{\mathrm{d}v}{\mathrm{d}t}$ and substitute for $t$ |
| $10\ (\text{ms}^{-2})$ towards $O$ | A1 | Correct only |

## Question 4(b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Integrate to obtain $x$: $x = -\frac{5}{2}\cos 2t\ (+C)$ | M1 | Use $x = \int v\,\mathrm{d}t$. Condone missing $+C$ |
| Use boundary conditions: $t = 0,\ x = 1 \Rightarrow C = \frac{7}{2}$ | M1 | Use boundary conditions to find $C$ |
| $x = \frac{7}{2} - \frac{5}{2}\cos 2t$ | A1 | Any equivalent form |
| $-1 \leq \cos 2t \leq 1 \Rightarrow 1 \leq x \leq 6$ | A1* | Deduce given answer from correct working |

## Question 4(c):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $x = \frac{7}{2} - \frac{5}{2}\cos 2t = 3 \Rightarrow \cos 2t = \frac{1}{5},\ t = 0.6847...$ | M1 | Use trig to find a relevant value of $t$ |
| Total time $= 4\pi - 8t$ | M1 | Correct method for the total time |
| $= 7.1\ \text{(s)}$ or better | A1 | $7.1\ \text{(s)}$ or better $7.08861...$ |
\begin{enumerate}
  \item A particle $P$ moves on the $x$-axis. At time $t$ seconds, $t \geqslant 0 , P$ is $x$ metres from the origin $O$ and moving with velocity $v \mathrm {~m} \mathrm {~s} ^ { - 1 }$ in the direction of $x$ increasing, where
\end{enumerate}

$$v = 5 \sin 2 t$$

When $t = 0 , x = 1$ and $P$ is at rest.\\
(a) Find the magnitude and direction of the acceleration of $P$ at the instant when $P$ is next at rest.\\
(b) Show that $1 \leqslant x \leqslant 6$\\
(c) Find the total time, in the first $4 \pi$ seconds of the motion, for which $P$ is more than 3 metres from $O$

\begin{center}
\includegraphics[max width=\textwidth, alt={}]{a7901165-1679-4d30-9444-0c27020e32ea-16_2260_52_309_1982}
\end{center}

\hfill \mbox{\textit{Edexcel FM2 AS 2021 Q4 [11]}}