| Exam Board | Edexcel |
|---|---|
| Module | FM1 AS (Further Mechanics 1 AS) |
| Session | Specimen |
| Marks | 16 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Momentum and Collisions 1 |
| Type | Collision followed by wall impact |
| Difficulty | Standard +0.8 This is a multi-part Further Maths mechanics question requiring conservation of momentum, coefficient of restitution equations, and careful analysis of collision conditions. Part (a)-(c) involve standard collision mechanics with algebraic manipulation, while part (d) requires sophisticated reasoning about when a second collision occurs after a wall rebound, involving inequalities and multiple velocity comparisons. The extended chain of reasoning and the need to track multiple collision scenarios elevates this above typical A-level questions. |
| Spec | 6.03b Conservation of momentum: 1D two particles6.03i Coefficient of restitution: e6.03j Perfectly elastic/inelastic: collisions6.03k Newton's experimental law: direct impact |
| VIIIV SIHI NI JIIIM ION OC | VIIIV SIHI NI JIHM I I ON OC | VIAV SIHI NI JIIIM I ON OC |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Use of conservation of momentum | M1 | For use of CLM, with correct no. of terms, condone sign errors |
| \(3mu - 2mu = 3mv + mw\) | A1 | For a correct equation |
| Use of NLR | M1 | For use of Newton's Law of Restitution, with \(e\) on the correct side |
| \(3ue = -v + w\) | A1 | For a correct equation |
| Using a correct strategy to solve, setting up two equations in \(u\) and \(v\) and solving for \(v\) | M1 | For setting up two equations and solving for \(v\) |
| \(v = \frac{u}{4}(1 - 3e)\) | A1 | For a correct expression for \(v\) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(\frac{u}{4}(1 - 3e) < 0\) | M1 | For use of an appropriate inequality |
| \(\frac{1}{3} < e \leq 1\) | A1 | For a complete range of values of \(e\) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Solving for \(w\) | M1 | For solving their equations for \(w\) |
| \(w = \frac{u}{4}(1 + 9e)\)* | A1* | For the given answer |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Substitute \(e = \frac{5}{9}\) | M1 | For substituting \(e = \frac{5}{9}\) into their \(v\) and \(w\) |
| \(v = -\frac{u}{6},\ w = \frac{3u}{2}\) | A1 | For correct expressions for \(v\) and \(w\) |
| Use NLR for impact with wall, \(x = fw\) | M1 | For use of Newton's Law of Restitution, with \(e\) on the correct side |
| Further collision if \(x > -v\) | M1 | For use of appropriate inequality |
| \(f\frac{3u}{2} > \frac{u}{6}\) | A1 | For a correct inequality |
| \(1 \geq f > \frac{1}{9}\) | A1 | For a correct range |
## Question 4:
### Part (a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Use of conservation of momentum | M1 | For use of CLM, with correct no. of terms, condone sign errors |
| $3mu - 2mu = 3mv + mw$ | A1 | For a correct equation |
| Use of NLR | M1 | For use of Newton's Law of Restitution, with $e$ on the correct side |
| $3ue = -v + w$ | A1 | For a correct equation |
| Using a correct strategy to solve, setting up two equations in $u$ and $v$ and solving for $v$ | M1 | For setting up two equations and solving for $v$ |
| $v = \frac{u}{4}(1 - 3e)$ | A1 | For a correct expression for $v$ |
### Part (b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\frac{u}{4}(1 - 3e) < 0$ | M1 | For use of an appropriate inequality |
| $\frac{1}{3} < e \leq 1$ | A1 | For a complete range of values of $e$ |
### Part (c):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Solving for $w$ | M1 | For solving their equations for $w$ |
| $w = \frac{u}{4}(1 + 9e)$* | A1* | For the given answer |
### Part (d):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Substitute $e = \frac{5}{9}$ | M1 | For substituting $e = \frac{5}{9}$ into their $v$ and $w$ |
| $v = -\frac{u}{6},\ w = \frac{3u}{2}$ | A1 | For correct expressions for $v$ and $w$ |
| Use NLR for impact with wall, $x = fw$ | M1 | For use of Newton's Law of Restitution, with $e$ on the correct side |
| Further collision if $x > -v$ | M1 | For use of appropriate inequality |
| $f\frac{3u}{2} > \frac{u}{6}$ | A1 | For a correct inequality |
| $1 \geq f > \frac{1}{9}$ | A1 | For a correct range |
\begin{enumerate}
\item A particle P of mass 3 m is moving in a straight line on a smooth horizontal table. A particle $Q$ of mass $m$ is moving in the opposite direction to $P$ along the same straight line. The particles collide directly. Immediately before the collision the speed of P is u and the speed of Q is 2 u . The velocities of P and Q immediately after the collision, measured in the direction of motion of P before the collision, are V and W respectively. The coefficient of restitution between P and Q is e .\\
(a) Find an expression for v in terms of u and e .
\end{enumerate}
Given that the direction of motion of P is changed by the collision,\\
(b) find the range of possible values of e.\\
(c) Show that $\mathrm { w } = \frac { \mathrm { u } } { 4 } ( 1 + 9 \mathrm { e } )$.
Following the collision with P , the particle Q then collides with and rebounds from a fixed vertical wall which is perpendicular to the direction of motion of $Q$. The coefficient of restitution between $Q$ and the wall is $f$.\\
Given that $\mathrm { e } = \frac { 5 } { 9 }$, and that P and Q collide again in the subsequent motion,\\
(d) find the range of possible values of f .
\begin{center}
\begin{tabular}{|l|l|l|}
\hline
VIIIV SIHI NI JIIIM ION OC & VIIIV SIHI NI JIHM I I ON OC & VIAV SIHI NI JIIIM I ON OC \\
\hline
\end{tabular}
\end{center}
\section*{Q uestion 4 continued}
\hfill \mbox{\textit{Edexcel FM1 AS Q4 [16]}}