Edexcel FS1 AS 2021 June — Question 3 12 marks

Exam BoardEdexcel
ModuleFS1 AS (Further Statistics 1 AS)
Year2021
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Random Variables
TypeExpectation and variance from distribution
DifficultyStandard +0.3 This is a straightforward Further Statistics question testing standard expectation/variance formulas and probability axioms. Parts (a)-(c) involve routine calculations with given distributions, while part (d) requires recognizing that P(W > T) = P(W > 3W - 8) simplifies to P(W < 4), which is a simple algebraic manipulation. All techniques are standard textbook exercises with no novel insight required, though the multi-part structure and Further Maths context place it slightly above average difficulty.
Spec5.02a Discrete probability distributions: general5.02b Expectation and variance: discrete random variables5.02c Linear coding: effects on mean and variance5.04a Linear combinations: E(aX+bY), Var(aX+bY)5.04b Linear combinations: of normal distributions

  1. The discrete random variable \(X\) has probability distribution
\(x\)- 3- 2- 1025
\(\mathrm { P } ( X = x )\)0.30.150.10.150.10.2
  1. Find \(\mathrm { E } ( X )\) Given that \(\operatorname { Var } ( X ) = 8.79\)
  2. find \(\mathrm { E } \left( X ^ { 2 } \right)\) The discrete random variable \(Y\) has probability distribution
    \(y\)- 2- 1012
    \(\mathrm { P } ( Y = y )\)\(3 a\)\(a\)\(b\)\(a\)\(c\)
    where \(a\), \(b\) and \(c\) are constants.
    For the random variable \(Y\) $$\mathrm { P } ( Y \leqslant 0 ) = 0.75 \quad \text { and } \quad \mathrm { E } \left( Y ^ { 2 } + 3 \right) = 5$$
  3. Find the value of \(a\), the value of \(b\) and the value of \(c\) The random variable \(W = Y - X\) where \(Y\) and \(X\) are independent.
    The random variable \(T = 3 W - 8\)
  4. Calculate \(\mathrm { P } ( W > T )\)

Question 3:
Part 3(a):
AnswerMarks Guidance
AnswerMark Guidance
\(E(X) = -0.1\) oeB1 \(-0.1\) oe
(1)
Part 3(b):
AnswerMarks Guidance
AnswerMark Guidance
\(\text{Var}(X) = E(X^2) - (\text{"-0.1"})^2\)M1 For recalling and using a correct formula
\(E(X^2) = 8.8\)A1 8.8
(2)
Part 3(c):
AnswerMarks Guidance
AnswerMark Guidance
\((-2)^2 \times 3a + (-1)^2 \times a[+0^2 \times b] + 1^2 \times a + 2^2 \times c = [\text{"2"}]\)M1 For use of \(\sum y^2 P(Y=y)[=2]\) or \(\sum(y^2+3)P(Y=y)[=5]\), 3 correct products seen
\(7a + 2c = 1\) oeA1 For correct equation with \(a\)'s collected
One of \(a+c=0.25\) or \(4a+b=0.75\) or \(5a+b+c=1\)M1 For use of \(\sum P(Y=y)=1\) or \(P(Y \leq 0)=0.75\) or \(1-P(Y \leq 0)=0.25\)
Two of \(a+c=0.25\) or \(4a+b=0.75\) or \(5a+b+c=1\)A1 For 2 correct equations
\(a=0.1\) and \(b=0.35\) and \(c=0.15\)A1 \(a\), \(b\) and \(c\) correct. Award full marks if all 3 correct
(5)
Part 3(d):
AnswerMarks Guidance
AnswerMark Guidance
\(P(W>T) = P(W > 3W-8) = P(W < 4)\)M1 For using the information given to work out the values of \(W\). Allow \(Y-X\) instead of \(W\)
\(P(W<4) = 1-[P(X=-3)\times P(Y=1) + P(X=-3)\times P(Y=2) + P(X=-2)\times P(Y=2)]\) or \(= P(X \geq -1) + P(X=-2)\times P(Y \neq 2) + P(X=-3)\times P(Y \leq 0)\)M1dep For using the information given to work out which are the relevant combinations of \(X\) and \(Y\). The irrelevant ones must not be used
\(= 1-[0.3\times\text{"0.1"}+0.3\times\text{"0.15"}+0.15\times\text{"0.15"}]\) or \(0.55 + 0.15\times[1-\text{"0.15"}]+0.3\times[\text{"0.3"}+\text{"0.1"}+\text{"0.35"}]\)M1dep Previous method must be awarded. All required cases identified and their probabilities of \(a\), \(b\) and \(c\) used. Allow in terms of \(a\), \(b\) and \(c\)
\(= \mathbf{0.9025}\)A1 0.9025 (accept awrt 0.903 or exact fraction \(\frac{361}{400}\))
(4)
# Question 3:

## Part 3(a):
| Answer | Mark | Guidance |
|--------|------|----------|
| $E(X) = -0.1$ oe | B1 | $-0.1$ oe |
| | **(1)** | |

## Part 3(b):
| Answer | Mark | Guidance |
|--------|------|----------|
| $\text{Var}(X) = E(X^2) - (\text{"-0.1"})^2$ | M1 | For recalling and using a correct formula |
| $E(X^2) = 8.8$ | A1 | 8.8 |
| | **(2)** | |

## Part 3(c):
| Answer | Mark | Guidance |
|--------|------|----------|
| $(-2)^2 \times 3a + (-1)^2 \times a[+0^2 \times b] + 1^2 \times a + 2^2 \times c = [\text{"2"}]$ | M1 | For use of $\sum y^2 P(Y=y)[=2]$ or $\sum(y^2+3)P(Y=y)[=5]$, 3 correct products seen |
| $7a + 2c = 1$ oe | A1 | For correct equation with $a$'s collected |
| One of $a+c=0.25$ **or** $4a+b=0.75$ **or** $5a+b+c=1$ | M1 | For use of $\sum P(Y=y)=1$ or $P(Y \leq 0)=0.75$ or $1-P(Y \leq 0)=0.25$ |
| Two of $a+c=0.25$ **or** $4a+b=0.75$ **or** $5a+b+c=1$ | A1 | For 2 correct equations |
| $a=0.1$ and $b=0.35$ and $c=0.15$ | A1 | $a$, $b$ and $c$ correct. Award full marks if all 3 correct |
| | **(5)** | |

## Part 3(d):
| Answer | Mark | Guidance |
|--------|------|----------|
| $P(W>T) = P(W > 3W-8) = P(W < 4)$ | M1 | For using the information given to work out the values of $W$. Allow $Y-X$ instead of $W$ |
| $P(W<4) = 1-[P(X=-3)\times P(Y=1) + P(X=-3)\times P(Y=2) + P(X=-2)\times P(Y=2)]$ **or** $= P(X \geq -1) + P(X=-2)\times P(Y \neq 2) + P(X=-3)\times P(Y \leq 0)$ | M1dep | For using the information given to work out which are the relevant combinations of $X$ and $Y$. The irrelevant ones must not be used |
| $= 1-[0.3\times\text{"0.1"}+0.3\times\text{"0.15"}+0.15\times\text{"0.15"}]$ **or** $0.55 + 0.15\times[1-\text{"0.15"}]+0.3\times[\text{"0.3"}+\text{"0.1"}+\text{"0.35"}]$ | M1dep | Previous method must be awarded. All required cases identified and their probabilities of $a$, $b$ and $c$ used. Allow in terms of $a$, $b$ and $c$ |
| $= \mathbf{0.9025}$ | A1 | 0.9025 (accept awrt 0.903 or exact fraction $\frac{361}{400}$) |
| | **(4)** | |

---
\begin{enumerate}
  \item The discrete random variable $X$ has probability distribution
\end{enumerate}

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | c | }
\hline
$x$ & - 3 & - 2 & - 1 & 0 & 2 & 5 \\
\hline
$\mathrm { P } ( X = x )$ & 0.3 & 0.15 & 0.1 & 0.15 & 0.1 & 0.2 \\
\hline
\end{tabular}
\end{center}

(a) Find $\mathrm { E } ( X )$

Given that $\operatorname { Var } ( X ) = 8.79$\\
(b) find $\mathrm { E } \left( X ^ { 2 } \right)$

The discrete random variable $Y$ has probability distribution

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | }
\hline
$y$ & - 2 & - 1 & 0 & 1 & 2 \\
\hline
$\mathrm { P } ( Y = y )$ & $3 a$ & $a$ & $b$ & $a$ & $c$ \\
\hline
\end{tabular}
\end{center}

where $a$, $b$ and $c$ are constants.\\
For the random variable $Y$

$$\mathrm { P } ( Y \leqslant 0 ) = 0.75 \quad \text { and } \quad \mathrm { E } \left( Y ^ { 2 } + 3 \right) = 5$$

(c) Find the value of $a$, the value of $b$ and the value of $c$

The random variable $W = Y - X$ where $Y$ and $X$ are independent.\\
The random variable $T = 3 W - 8$\\
(d) Calculate $\mathrm { P } ( W > T )$

\hfill \mbox{\textit{Edexcel FS1 AS 2021 Q3 [12]}}