CAIE P3 2021 November — Question 10 11 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2021
SessionNovember
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeIterative/numerical methods
DifficultyStandard +0.8 This is a substantial multi-part question requiring: (a) setting up a differential equation from a word problem with proportionality, (b) solving using separation of variables with partial fractions and logarithms, then rearranging to a specific form, (c) applying iterative methods, and (d) finding a limiting value. The separation and algebraic manipulation in part (b) is non-trivial, and the question tests multiple techniques across 4 parts. However, each individual step follows standard A-level methods without requiring novel insight.
Spec1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams4.10a General/particular solutions: of differential equations4.10b Model with differential equations: kinematics and other contexts4.10c Integrating factor: first order equations

10 A large plantation of area \(20 \mathrm {~km} ^ { 2 }\) is becoming infected with a plant disease. At time \(t\) years the area infected is \(x \mathrm {~km} ^ { 2 }\) and the rate of increase of \(x\) is proportional to the ratio of the area infected to the area not yet infected. When \(t = 0 , x = 1\) and \(\frac { \mathrm { d } x } { \mathrm {~d} t } = 1\).
  1. Show that \(x\) and \(t\) satisfy the differential equation $$\frac { \mathrm { d } x } { \mathrm {~d} t } = \frac { 19 x } { 20 - x }$$
  2. Solve the differential equation and show that when \(t = 1\) the value of \(x\) satisfies the equation \(x = \mathrm { e } ^ { 0.9 + 0.05 x }\).
  3. Use an iterative formula based on the equation in part (b), with an initial value of 2 , to determine \(x\) correct to 2 decimal places. Give the result of each iteration to 4 decimal places.
  4. Calculate the value of \(t\) at which the entire plantation becomes infected.

Question 10(a):
AnswerMarks Guidance
AnswerMarks Guidance
State or imply equation of the form \(\frac{\mathrm{d}x}{\mathrm{d}t} = k\,\frac{x}{20-x}\)M1
Obtain \(k = 19\)A1 AG
Total2
Question 10(b):
AnswerMarks Guidance
AnswerMarks Guidance
Separate variables and integrate at least one sideM1
Obtain terms \(20\ln x - x\) and \(19t\), or equivalentA1 A1
Evaluate a constant or use \(t = 0\) and \(x = 1\) as limits in a solution containing terms \(a\ln x\) and \(bt\)M1
Substitute \(t = 1\) and rearrange the equation in the given formA1 AG
Total5
Question 10(c):
AnswerMarks Guidance
AnswerMarks Guidance
Use \(x_{n+1} = e^{0.9+0.05x_n}\) correctly at least onceM1
Obtain final answer \(x = 2.83\)A1
Show sufficient iterations to 4 decimal places to justify 2.83 to 2 d.p. or show there is a sign change in the interval \((2.825,\, 2.835)\)A1
Total3
Question 10(d):
AnswerMarks Guidance
AnswerMarks Guidance
Set \(x = 20\) and obtain answer \(t = 2.15\)B1
Total1
## Question 10(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| State or imply equation of the form $\frac{\mathrm{d}x}{\mathrm{d}t} = k\,\frac{x}{20-x}$ | M1 | |
| Obtain $k = 19$ | A1 | AG |
| **Total** | **2** | |

## Question 10(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Separate variables and integrate at least one side | M1 | |
| Obtain terms $20\ln x - x$ and $19t$, or equivalent | A1 A1 | |
| Evaluate a constant or use $t = 0$ and $x = 1$ as limits in a solution containing terms $a\ln x$ and $bt$ | M1 | |
| Substitute $t = 1$ and rearrange the equation in the given form | A1 | AG |
| **Total** | **5** | |

## Question 10(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Use $x_{n+1} = e^{0.9+0.05x_n}$ correctly at least once | M1 | |
| Obtain final answer $x = 2.83$ | A1 | |
| Show sufficient iterations to 4 decimal places to justify 2.83 to 2 d.p. or show there is a sign change in the interval $(2.825,\, 2.835)$ | A1 | |
| **Total** | **3** | |

## Question 10(d):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Set $x = 20$ and obtain answer $t = 2.15$ | B1 | |
| **Total** | **1** | |
10 A large plantation of area $20 \mathrm {~km} ^ { 2 }$ is becoming infected with a plant disease. At time $t$ years the area infected is $x \mathrm {~km} ^ { 2 }$ and the rate of increase of $x$ is proportional to the ratio of the area infected to the area not yet infected.

When $t = 0 , x = 1$ and $\frac { \mathrm { d } x } { \mathrm {~d} t } = 1$.
\begin{enumerate}[label=(\alph*)]
\item Show that $x$ and $t$ satisfy the differential equation

$$\frac { \mathrm { d } x } { \mathrm {~d} t } = \frac { 19 x } { 20 - x }$$
\item Solve the differential equation and show that when $t = 1$ the value of $x$ satisfies the equation $x = \mathrm { e } ^ { 0.9 + 0.05 x }$.
\item Use an iterative formula based on the equation in part (b), with an initial value of 2 , to determine $x$ correct to 2 decimal places. Give the result of each iteration to 4 decimal places.
\item Calculate the value of $t$ at which the entire plantation becomes infected.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2021 Q10 [11]}}