- (a) Use the substitution \(t = \tan \left( \frac { x } { 2 } \right)\) to show that the equation
$$3 \cos x - 2 \sin x = 1$$
can be written in the form
$$2 t ^ { 2 } + 2 t - 1 = 0$$
(b) Hence solve, for \(- 180 ^ { \circ } < x < 180 ^ { \circ }\), the equation
$$3 \cos x - 2 \sin x = 1$$
giving your answers to one decimal place.