Edexcel CP AS Specimen — Question 5 7 marks

Exam BoardEdexcel
ModuleCP AS (Core Pure AS)
SessionSpecimen
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear transformations
TypeExtract enlargement and rotation parameters
DifficultyModerate -0.5 Standard Core Pure question on matrix transformations: finding determinant (trivial), using det for area scale factor, then identifying enlargement scale factor k=√(det M)=2 and rotation angle θ=60° by comparing to standard rotation-enlargement matrix form. All parts are routine with no novel insight required.
Spec4.03h Determinant 2x2: calculation4.03i Determinant: area scale factor and orientation

5. $$\mathbf { M } = \left( \begin{array} { c c } 1 & - \sqrt { 3 } \\ \sqrt { 3 } & 1 \end{array} \right)$$
  1. Show that \(\mathbf { M }\) is non-singular. The hexagon \(R\) is transformed to the hexagon \(S\) by the transformation represented by the matrix \(\mathbf { M }\). Given that the area of hexagon \(R\) is 5 square units,
  2. find the area of hexagon \(S\). The matrix \(\mathbf { M }\) represents an enlargement, with centre \(( 0,0 )\) and scale factor \(k\), where \(k > 0\), followed by a rotation anti-clockwise through an angle \(\theta\) about \(( 0,0 )\).
  3. Find the value of \(k\).
  4. Find the value of \(\theta\).

Question 5:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\det(\mathbf{M})=(1)(1)-(\sqrt{3})(-\sqrt{3})\)M1 An attempt to find \(\det(\mathbf{M})\)
\(\mathbf{M}\) is non-singular because \(\det(\mathbf{M})=4\) and so \(\det(\mathbf{M})\neq 0\)A1 \(\det(\mathbf{M})=4\) and reference to zero, e.g. \(4\neq 0\) and conclusion
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\text{Area}(S)=4(5)=20\)B1ft 20 or a correct ft based on their answer to part (a)
Part (c):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(k=\sqrt{(1)(1)-(\sqrt{3})(-\sqrt{3})}\)M1 \(\sqrt{\text{their }\det(\mathbf{M})}\)
\(k=2\)A1ft
Part (d):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\cos\theta=\dfrac{1}{2}\) or \(\sin\theta=\dfrac{\sqrt{3}}{2}\) or \(\tan\theta=\sqrt{3}\)M1 Either \(\cos\theta=\dfrac{1}{\text{their }k}\) or \(\sin\theta=\dfrac{\sqrt{3}}{\text{their }k}\) or \(\tan\theta=\sqrt{3}\)
\(\theta=60°\) or \(\dfrac{\pi}{3}\)A1 Also accept any value satisfying \(360n+60°\), \(n\in\mathbb{Z}\)
# Question 5:

## Part (a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\det(\mathbf{M})=(1)(1)-(\sqrt{3})(-\sqrt{3})$ | M1 | An attempt to find $\det(\mathbf{M})$ |
| $\mathbf{M}$ is non-singular because $\det(\mathbf{M})=4$ and so $\det(\mathbf{M})\neq 0$ | A1 | $\det(\mathbf{M})=4$ **and** reference to zero, e.g. $4\neq 0$ **and** conclusion |

## Part (b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\text{Area}(S)=4(5)=20$ | B1ft | 20 or a correct ft based on their answer to part (a) |

## Part (c):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $k=\sqrt{(1)(1)-(\sqrt{3})(-\sqrt{3})}$ | M1 | $\sqrt{\text{their }\det(\mathbf{M})}$ |
| $k=2$ | A1ft | |

## Part (d):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\cos\theta=\dfrac{1}{2}$ or $\sin\theta=\dfrac{\sqrt{3}}{2}$ or $\tan\theta=\sqrt{3}$ | M1 | Either $\cos\theta=\dfrac{1}{\text{their }k}$ or $\sin\theta=\dfrac{\sqrt{3}}{\text{their }k}$ or $\tan\theta=\sqrt{3}$ |
| $\theta=60°$ or $\dfrac{\pi}{3}$ | A1 | Also accept any value satisfying $360n+60°$, $n\in\mathbb{Z}$ |
5.

$$\mathbf { M } = \left( \begin{array} { c c } 
1 & - \sqrt { 3 } \\
\sqrt { 3 } & 1
\end{array} \right)$$
\begin{enumerate}[label=(\alph*)]
\item Show that $\mathbf { M }$ is non-singular.

The hexagon $R$ is transformed to the hexagon $S$ by the transformation represented by the matrix $\mathbf { M }$.

Given that the area of hexagon $R$ is 5 square units,
\item find the area of hexagon $S$.

The matrix $\mathbf { M }$ represents an enlargement, with centre $( 0,0 )$ and scale factor $k$, where $k > 0$, followed by a rotation anti-clockwise through an angle $\theta$ about $( 0,0 )$.
\item Find the value of $k$.
\item Find the value of $\theta$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel CP AS  Q5 [7]}}