WJEC Further Unit 6 2023 June — Question 4 15 marks

Exam BoardWJEC
ModuleFurther Unit 6 (Further Unit 6)
Year2023
SessionJune
Marks15
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Mark schemeDownload PDF ↗
TopicCentre of Mass 1
TypeLamina with particle - suspended equilibrium
DifficultyChallenging +1.2 This is a multi-part centre of mass problem requiring systematic calculation of composite system COM, then applying equilibrium conditions for suspended bodies. Part (a) involves standard COM formulas for particles and a quarter-circle lamina (requiring the formula for quarter-circle centroid). Parts (b) and (c) apply the principle that a suspended body hangs with COM directly below the suspension point. While lengthy with multiple components, the techniques are standard for Further Maths mechanics with no novel geometric insight required. The 60° angle in part (c) adds mild trigonometry but remains routine.
Spec6.04b Find centre of mass: using symmetry6.04c Composite bodies: centre of mass6.04d Integration: for centre of mass of laminas/solids6.04e Rigid body equilibrium: coplanar forces

4. The diagram shows three light rods \(A B , B C\) and \(C A\) rigidly joined together so that \(A B C\) is a right-angled triangle with \(A B = 45 \mathrm {~cm} , A C = 28 \mathrm {~cm}\) and \(\widehat { A B } = 90 ^ { \circ }\). The rods support a uniform lamina, of density \(2 m \mathrm {~kg} / \mathrm { cm } ^ { 2 }\), in the shape of a quarter circle \(A D E\) with radius 12 cm and centre at the vertex \(A\). Three particles are attached to \(B C\) : one at \(B\), one at \(C\) and one at \(F\), the midpoint of \(B C\). The masses at \(C , F\) and \(B\) are \(50 m \mathrm {~kg} , 30 m \mathrm {~kg}\) and \(20 m \mathrm {~kg}\) respectively. \includegraphics[max width=\textwidth, alt={}, center]{d7f600c5-af4a-4708-bfd9-92b37a95c634-5_604_908_756_575}
  1. Calculate the distance of the centre of mass of the system from
    1. \(A C\),
    2. \(A B\).
  2. When the system is freely suspended from a point \(P\) on \(A C\), it hangs in equilibrium with \(A B\) vertical. Write down the length \(A P\).
  3. When the system is freely suspended from a point \(Q\) on \(A D\), it hangs in equilibrium with \(Q B\) making an angle of \(60 ^ { \circ }\) with the vertical. Find the distance \(A Q\).

4. The diagram shows three light rods $A B , B C$ and $C A$ rigidly joined together so that $A B C$ is a right-angled triangle with $A B = 45 \mathrm {~cm} , A C = 28 \mathrm {~cm}$ and $\widehat { A B } = 90 ^ { \circ }$. The rods support a uniform lamina, of density $2 m \mathrm {~kg} / \mathrm { cm } ^ { 2 }$, in the shape of a quarter circle $A D E$ with radius 12 cm and centre at the vertex $A$. Three particles are attached to $B C$ : one at $B$, one at $C$ and one at $F$, the midpoint of $B C$.

The masses at $C , F$ and $B$ are $50 m \mathrm {~kg} , 30 m \mathrm {~kg}$ and $20 m \mathrm {~kg}$ respectively.\\
\includegraphics[max width=\textwidth, alt={}, center]{d7f600c5-af4a-4708-bfd9-92b37a95c634-5_604_908_756_575}
\begin{enumerate}[label=(\alph*)]
\item Calculate the distance of the centre of mass of the system from
\begin{enumerate}[label=(\roman*)]
\item $A C$,
\item $A B$.
\end{enumerate}\item When the system is freely suspended from a point $P$ on $A C$, it hangs in equilibrium with $A B$ vertical. Write down the length $A P$.
\item When the system is freely suspended from a point $Q$ on $A D$, it hangs in equilibrium with $Q B$ making an angle of $60 ^ { \circ }$ with the vertical. Find the distance $A Q$.
\end{enumerate}

\hfill \mbox{\textit{WJEC Further Unit 6 2023 Q4 [15]}}