WJEC Further Unit 6 2019 June — Question 6 12 marks

Exam BoardWJEC
ModuleFurther Unit 6 (Further Unit 6)
Year2019
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeLadder on smooth wall and rough ground
DifficultyChallenging +1.2 This is a standard ladder equilibrium problem requiring resolution of forces, taking moments, and finding a limiting friction coefficient. While it involves multiple steps (showing a given result, then optimization), the techniques are routine for Further Maths mechanics students. The geometry interpretation (CB:CA = 1:4) adds mild complexity but the overall approach is textbook-standard for this topic.
Spec3.03r Friction: concept and vector form3.03u Static equilibrium: on rough surfaces6.04e Rigid body equilibrium: coplanar forces

6. \includegraphics[max width=\textwidth, alt={}, center]{3578a810-46da-4d9e-a98f-248be72a517a-7_606_506_365_781} A uniform ladder \(A B\), of mass 10 kg and length 5 m , rests with one end \(A\) against a smooth vertical wall and the other end \(B\) on rough horizontal ground. The ladder is inclined at an angle \(\theta\) to the horizontal. A woman of mass 75 kg stands on the ladder so that her weight acts at a distance \(x \mathrm {~m}\) from \(B\).
  1. Show that the frictional force, \(F \mathrm {~N}\), between the ladder and the horizontal ground is given by $$F = 5 g \cot \theta ( 1 + 3 x ) .$$ For safety reasons, it is recommended that \(\theta\) is chosen such that the ratio \(C B : C A\) is \(1 : 4\).
  2. Determine the least value of the coefficient of friction such that the ladder will not slip however high the woman climbs.
  3. State one modelling assumption that you have made in your solution.

6.\\
\includegraphics[max width=\textwidth, alt={}, center]{3578a810-46da-4d9e-a98f-248be72a517a-7_606_506_365_781}

A uniform ladder $A B$, of mass 10 kg and length 5 m , rests with one end $A$ against a smooth vertical wall and the other end $B$ on rough horizontal ground. The ladder is inclined at an angle $\theta$ to the horizontal. A woman of mass 75 kg stands on the ladder so that her weight acts at a distance $x \mathrm {~m}$ from $B$.
\begin{enumerate}[label=(\alph*)]
\item Show that the frictional force, $F \mathrm {~N}$, between the ladder and the horizontal ground is given by

$$F = 5 g \cot \theta ( 1 + 3 x ) .$$

For safety reasons, it is recommended that $\theta$ is chosen such that the ratio $C B : C A$ is $1 : 4$.
\item Determine the least value of the coefficient of friction such that the ladder will not slip however high the woman climbs.
\item State one modelling assumption that you have made in your solution.
\end{enumerate}

\hfill \mbox{\textit{WJEC Further Unit 6 2019 Q6 [12]}}