CAIE P3 2022 March — Question 4 5 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2022
SessionMarch
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicParametric differentiation
TypeShow dy/dx simplifies to given form
DifficultyModerate -0.3 This is a straightforward parametric differentiation question requiring standard application of dy/dx = (dy/dθ)/(dx/dθ), followed by routine trigonometric simplification using double angle formulas. The algebra is mechanical with no problem-solving insight needed, making it slightly easier than average but not trivial due to the multi-step trigonometric manipulation required.
Spec1.03g Parametric equations: of curves and conversion to cartesian1.07s Parametric and implicit differentiation

4 The parametric equations of a curve are $$x = 1 - \cos \theta , \quad y = \cos \theta - \frac { 1 } { 4 } \cos 2 \theta$$ Show that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = - 2 \sin ^ { 2 } \left( \frac { 1 } { 2 } \theta \right)\).

Question 4:
AnswerMarks Guidance
AnswerMark Guidance
State \(\frac{dx}{d\theta} = \sin\theta\) or \(\frac{dy}{d\theta} = -\sin\theta + \frac{1}{2}\sin 2\theta\)B1
Use \(\frac{dy}{dx} = \frac{dy}{d\theta} \div \frac{dx}{d\theta}\)M1
Obtain correct answer in any formA1 e.g. \(\dfrac{-\sin\theta + \frac{1}{2}\sin 2\theta}{\sin\theta}\)
Use double angle correctly to obtain \(\frac{dy}{dx}\) in terms of \(\theta\)M1 \(\sin 2\theta = 2\sin\theta\cos\theta\)
Obtain the given answer with no errors seen \(-2\sin^2\!\left(\frac{1}{2}\theta\right)\)A1 AG. Requires correct cancellation of ALL \(\sin\theta\) terms and \(\cos\theta = 1 - 2\sin^2\!\left(\frac{1}{2}\theta\right)\) seen. SC for incorrect signs, consistent throughout max. B0, M1, A0, M1, A1
Total: 5
## Question 4:

| Answer | Mark | Guidance |
|--------|------|----------|
| State $\frac{dx}{d\theta} = \sin\theta$ or $\frac{dy}{d\theta} = -\sin\theta + \frac{1}{2}\sin 2\theta$ | B1 | |
| Use $\frac{dy}{dx} = \frac{dy}{d\theta} \div \frac{dx}{d\theta}$ | M1 | |
| Obtain correct answer in any form | A1 | e.g. $\dfrac{-\sin\theta + \frac{1}{2}\sin 2\theta}{\sin\theta}$ |
| Use double angle correctly to obtain $\frac{dy}{dx}$ in terms of $\theta$ | M1 | $\sin 2\theta = 2\sin\theta\cos\theta$ |
| Obtain the given answer with no errors seen $-2\sin^2\!\left(\frac{1}{2}\theta\right)$ | A1 | AG. Requires correct cancellation of ALL $\sin\theta$ terms and $\cos\theta = 1 - 2\sin^2\!\left(\frac{1}{2}\theta\right)$ seen. SC for incorrect signs, consistent throughout max. B0, M1, A0, M1, A1 |
| **Total: 5** | | |

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4 The parametric equations of a curve are

$$x = 1 - \cos \theta , \quad y = \cos \theta - \frac { 1 } { 4 } \cos 2 \theta$$

Show that $\frac { \mathrm { d } y } { \mathrm {~d} x } = - 2 \sin ^ { 2 } \left( \frac { 1 } { 2 } \theta \right)$.\\

\hfill \mbox{\textit{CAIE P3 2022 Q4 [5]}}