Edexcel M5 2006 January — Question 3 6 marks

Exam BoardEdexcel
ModuleM5 (Mechanics 5)
Year2006
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeStandard linear first order - vector form
DifficultyStandard +0.3 This is a straightforward application of the integrating factor method to a vector differential equation with constant coefficients. While the vector context adds slight novelty compared to scalar versions, the solution is mechanical: identify integrating factor e^(2t), multiply through, integrate, and apply initial conditions. The 6 marks reflect routine execution rather than conceptual challenge, making it slightly easier than average.
Spec3.04a Calculate moments: about a point4.10f Simple harmonic motion: x'' = -omega^2 x6.04e Rigid body equilibrium: coplanar forces

3. The position vector \(\mathbf { r }\) of a particle \(P\) at time \(t\) satisfies the vector differential equation $$\frac { \mathrm { d } \mathbf { r } } { \mathrm {~d} t } + 2 \mathbf { r } = 4 \mathbf { i }$$ Given that the position vector of \(P\) at time \(t = 0\) is \(2 \mathbf { j }\), find the position vector of \(P\) at time \(t\).
(Total 6 marks)

3. The position vector $\mathbf { r }$ of a particle $P$ at time $t$ satisfies the vector differential equation

$$\frac { \mathrm { d } \mathbf { r } } { \mathrm {~d} t } + 2 \mathbf { r } = 4 \mathbf { i }$$

Given that the position vector of $P$ at time $t = 0$ is $2 \mathbf { j }$, find the position vector of $P$ at time $t$.\\
(Total 6 marks)\\

\hfill \mbox{\textit{Edexcel M5 2006 Q3 [6]}}