5 A uniform rectangular lamina \(A B C D\) has mass 20 kg and sides of lengths \(A B = 0.6 \mathrm {~m}\) and \(B C = 1.8 \mathrm {~m}\). It rotates in its own vertical plane about a fixed horizontal axis which is perpendicular to the lamina and passes through the mid-point of \(A B\).
- Show that the moment of inertia of the lamina about the axis is \(22.2 \mathrm {~kg} \mathrm {~m} ^ { 2 }\).
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The lamina is released from rest with \(B C\) horizontal and below the level of the axis. Air resistance may be neglected, but a frictional couple opposes the motion. The couple has constant moment 44.1 Nm about the axis. The angle through which the lamina has turned is denoted by \(\theta\) (see diagram). - Show that the angular acceleration is zero when \(\cos \theta = 0.25\).
- Hence find the maximum angular speed of the lamina.
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A ship \(P\) is moving with constant velocity \(7 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) in the direction with bearing \(110 ^ { \circ }\). A second ship \(Q\) is moving with constant speed \(10 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) in a straight line. At one instant \(Q\) is at the point \(X\), and \(P\) is 7400 m from \(Q\) on a bearing of \(050 ^ { \circ }\) (see diagram). In the subsequent motion, the shortest distance between \(P\) and \(Q\) is 1790 m . - Show that one possible direction for the velocity of \(Q\) relative to \(P\) has bearing \(036 ^ { \circ }\), to the nearest degree, and find the bearing of the other possible direction of this relative velocity.
Given that the velocity of \(Q\) relative to \(P\) has bearing \(036 ^ { \circ }\), find
- the bearing of the direction in which \(Q\) is moving,
- the magnitude of the velocity of \(Q\) relative to \(P\),
- the time taken for \(Q\) to travel from \(X\) to the position where the two ships are closest together,
- the bearing of \(P\) from \(Q\) when the two ships are closest together.
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A uniform rod \(A B\) has mass \(m\) and length \(6 a\). It is free to rotate in a vertical plane about a smooth fixed horizontal axis passing through the point \(C\) on the rod, where \(A C = a\). The angle between \(A B\) and the upward vertical is \(\theta\), and the force acting on the rod at \(C\) has components \(R\) parallel to \(A B\) and \(S\) perpendicular to \(A B\) (see diagram). The rod is released from rest in the position where \(\theta = \frac { 1 } { 3 } \pi\). Air resistance may be neglected. - Find the angular acceleration of the rod in terms of \(a , g\) and \(\theta\).
- Show that the angular speed of the rod is \(\sqrt { \frac { 2 g ( 1 - 2 \cos \theta ) } { 7 a } }\).
- Find \(R\) and \(S\) in terms of \(m , g\) and \(\theta\).
- When \(\cos \theta = \frac { 1 } { 3 }\), show that the force acting on the rod at \(C\) is vertical, and find its magnitude.