Edexcel M4 2018 June — Question 1 11 marks

Exam BoardEdexcel
ModuleM4 (Mechanics 4)
Year2018
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypePotential energy with elastic strings/springs
DifficultyChallenging +1.8 This is a Further Maths M4 question requiring potential energy formulation (gravitational + elastic) and stability analysis via second derivative. While methodical, it demands careful geometry, correct PE expressions for both components, differentiation, and understanding of equilibrium stability criteria—significantly above standard A-level but follows established M4 techniques.
Spec6.02d Mechanical energy: KE and PE concepts6.02e Calculate KE and PE: using formulae6.04d Integration: for centre of mass of laminas/solids

1. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{e0f141c7-ecd0-4f62-bfad-76c81c2d6396-02_538_881_278_534} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} A uniform rod \(A B\) has mass \(m\) and length 4a. The end \(A\) of the rod is freely hinged to a fixed point. One end of a light elastic string, of natural length \(a\) and modulus \(\frac { 1 } { 4 } m g\), is attached to the end \(B\) of the rod. The other end of the string is attached to a small light smooth ring \(R\). The ring can move freely on a smooth horizontal wire which is fixed at a height \(a\) above \(A\), and in a vertical plane through \(A\). The angle between the rod and the horizontal is \(\theta\), where \(0 < \theta < \frac { \pi } { 2 }\), as shown in Figure 1. Given that the elastic string is vertical,
  1. show that the potential energy of the system is $$2 m g a \left( \sin ^ { 2 } \theta - \sin \theta \right) + \text { constant }$$
  2. Show that when \(\theta = \frac { \pi } { 6 }\) the rod is in stable equilibrium.

1.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{e0f141c7-ecd0-4f62-bfad-76c81c2d6396-02_538_881_278_534}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

A uniform rod $A B$ has mass $m$ and length 4a. The end $A$ of the rod is freely hinged to a fixed point. One end of a light elastic string, of natural length $a$ and modulus $\frac { 1 } { 4 } m g$, is attached to the end $B$ of the rod. The other end of the string is attached to a small light smooth ring $R$. The ring can move freely on a smooth horizontal wire which is fixed at a height $a$ above $A$, and in a vertical plane through $A$. The angle between the rod and the horizontal is $\theta$, where $0 < \theta < \frac { \pi } { 2 }$, as shown in Figure 1. Given that the elastic string is vertical,
\begin{enumerate}[label=(\alph*)]
\item show that the potential energy of the system is

$$2 m g a \left( \sin ^ { 2 } \theta - \sin \theta \right) + \text { constant }$$
\item Show that when $\theta = \frac { \pi } { 6 }$ the rod is in stable equilibrium.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M4 2018 Q1 [11]}}