Edexcel M3 — Question 2 8 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAdvanced work-energy problems
TypeVariable force along axis work-energy
DifficultyStandard +0.3 This is a straightforward application of work-energy principles with integration. Part (a) requires integrating a simple exponential function (5 + 4e^(-x)) from 0 to 1, which is routine M3 content. Part (b) applies the work-energy theorem directly using the result from (a). Both parts follow standard textbook procedures with no novel problem-solving required, making it slightly easier than average.
Spec6.02c Work by variable force: using integration6.02i Conservation of energy: mechanical energy principle

2. A particle \(P\) of mass 0.4 kg is moving in a straight line through a fixed point \(O\). At time \(t\) seconds after it passes through \(O\), the distance \(O P\) is \(x\) metres and the resultant force acting on \(P\) is of magnitude ( \(5 + 4 \mathrm { e } ^ { - x }\) ) N in the direction \(O P\). When \(x = 1 , P\) is at the point \(A\).
  1. Find, correct to 3 significant figures, the work done in moving \(P\) from \(O\) to \(A\). Given that \(P\) passes through \(O\) with speed \(2 \mathrm {~ms} ^ { - 1 }\),
  2. find, correct to 3 significant figures, the speed of \(P\) as it passes through \(A\).

AnswerMarks Guidance
work done \(= \int_0^1 5 + 4e^{-x} \, dx = [5x - 4e^{-x}]_0^1\)M1 A1
\(= (5 - 4e^{-1}) - (0 - 4) = 9 - 4e^{-1} = 7.53 \text{ J (3sf)}\)M1 A1
work done \(=\) change in KEM1
\(9 - 4e^{-1} = \frac{1}{2} \times 0.4 \times (v^2 - 2^2)\)M1 A1
giving \(v = 6.45 \text{ ms}^{-1} \text{ (3sf)}\)A1 (8)
work done $= \int_0^1 5 + 4e^{-x} \, dx = [5x - 4e^{-x}]_0^1$ | M1 A1 |
$= (5 - 4e^{-1}) - (0 - 4) = 9 - 4e^{-1} = 7.53 \text{ J (3sf)}$ | M1 A1 |

work done $=$ change in KE | M1 |
$9 - 4e^{-1} = \frac{1}{2} \times 0.4 \times (v^2 - 2^2)$ | M1 A1 |
giving $v = 6.45 \text{ ms}^{-1} \text{ (3sf)}$ | A1 | (8)
2. A particle $P$ of mass 0.4 kg is moving in a straight line through a fixed point $O$.

At time $t$ seconds after it passes through $O$, the distance $O P$ is $x$ metres and the resultant force acting on $P$ is of magnitude ( $5 + 4 \mathrm { e } ^ { - x }$ ) N in the direction $O P$.

When $x = 1 , P$ is at the point $A$.
\begin{enumerate}[label=(\alph*)]
\item Find, correct to 3 significant figures, the work done in moving $P$ from $O$ to $A$.

Given that $P$ passes through $O$ with speed $2 \mathrm {~ms} ^ { - 1 }$,
\item find, correct to 3 significant figures, the speed of $P$ as it passes through $A$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M3  Q2 [8]}}