Edexcel M2 — Question 2 8 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeWork done against friction/resistance - inclined plane or slope
DifficultyModerate -0.3 This is a straightforward M2 energy question requiring standard application of KE and PE formulas with given values. Part (a) involves routine calculation (change in KE + change in PE) with no conceptual difficulty, while part (b) is simple recall of resistance forces. Slightly easier than average due to explicit guidance and standard bookwork nature.
Spec6.02d Mechanical energy: KE and PE concepts6.02e Calculate KE and PE: using formulae

2. A car of mass 1 tonne is climbing a hill inclined at an angle \(\theta\) to the horizontal where \(\sin \theta = \frac { 1 } { 7 }\). When the car passes a point \(X\) on the hill, it is travelling at \(20 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). When the car passes the point \(Y , 200 \mathrm {~m}\) further up the hill, it has speed \(10 \mathrm {~ms} ^ { - 1 }\). In a preliminary model of the situation, the car engine is assumed only to be doing work against gravity. Using this model,
  1. find the change in the total mechanical energy of the car as it moves from \(X\) to \(Y\).
    (6 marks)
    In a more sophisticated model, the car engine is also assumed to work against other forces.
  2. Write down two other forces which this model might include.
    (2 marks)

Question 2:
AnswerMarks Guidance
Answer/WorkingMarks Notes
(a) change in KE \(= \frac{1}{2} \times 1000(10^2 - 20^2) = -150000\) JM1 A1
change in PE \(= 1000(9.8)(200\sin\theta) = 280000\) JM2 A1
change in ME \(= 280000 - 150000 =\) increase of \(130000\) JA1
(b) air resistanceB1
frictionB1 (8)
## Question 2:

| Answer/Working | Marks | Notes |
|---|---|---|
| **(a)** change in KE $= \frac{1}{2} \times 1000(10^2 - 20^2) = -150000$ J | M1 A1 | |
| change in PE $= 1000(9.8)(200\sin\theta) = 280000$ J | M2 A1 | |
| change in ME $= 280000 - 150000 =$ increase of $130000$ J | A1 | |
| **(b)** air resistance | B1 | |
| friction | B1 | **(8)** |

---
2. A car of mass 1 tonne is climbing a hill inclined at an angle $\theta$ to the horizontal where $\sin \theta = \frac { 1 } { 7 }$. When the car passes a point $X$ on the hill, it is travelling at $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. When the car passes the point $Y , 200 \mathrm {~m}$ further up the hill, it has speed $10 \mathrm {~ms} ^ { - 1 }$.

In a preliminary model of the situation, the car engine is assumed only to be doing work against gravity. Using this model,
\begin{enumerate}[label=(\alph*)]
\item find the change in the total mechanical energy of the car as it moves from $X$ to $Y$.\\
(6 marks)\\
In a more sophisticated model, the car engine is also assumed to work against other forces.
\item Write down two other forces which this model might include.\\
(2 marks)
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2  Q2 [8]}}