Fig 3.2 shows a non-uniform rod of length 6 m and weight 68 N with its centre of mass at G . This rod is free to rotate in a vertical plane about a horizontal axis through B , which is 2 m from A . G is 2 m from B . The rod is held in equilibrium at an angle \(\theta\) to the horizontal by a horizontal force of 102 N acting at C and another force acting at A (not shown in Fig. 3.2). Both of these forces and the force exerted on the rod by the hinge (also not shown in Fig 3.2) act in a vertical plane containing the rod. You are given that \(\sin \theta = \frac { 15 } { 17 }\).
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{334b2170-3708-46db-bff7-bcad7d5fab00-4_396_314_1747_852}
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\caption{Fig. 3.2}
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- First suppose that the force at A is at right angles to ABC and has magnitude \(P \mathrm {~N}\).
Calculate \(P\).
- Now instead suppose that the force at A is horizontal and has magnitude \(Q \mathrm {~N}\).
Calculate \(Q\).
Calculate also the magnitude of the force exerted on the rod by the hinge.