OCR M2 2015 June — Question 3 6 marks

Exam BoardOCR
ModuleM2 (Mechanics 2)
Year2015
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPower and driving force
TypeFind power and resistance simultaneously
DifficultyStandard +0.3 This is a standard M2 power-speed-acceleration problem requiring two simultaneous equations from P=Fv at two different points. The method is routine (F=ma to find driving force, then P=Fv), though the algebra with two unknowns and specific numerical values requires careful execution. Slightly above average due to the simultaneous equation solving, but well within typical M2 scope.
Spec6.02l Power and velocity: P = Fv

3 A car of mass 1500 kg travels along a straight horizontal road with its engine working at a constant rate of \(P \mathrm {~W}\). There is a constant resistance to motion of \(R \mathrm {~N}\). Points \(A\) and \(B\) are on the road. At point \(A\) the car's speed is \(16 \mathrm {~ms} ^ { - 1 }\) and its acceleration is \(0.3875 \mathrm {~ms} ^ { - 2 }\). At point \(B\) the car's speed is \(25 \mathrm {~ms} ^ { - 1 }\) and its acceleration is \(0.2 \mathrm {~ms} ^ { - 2 }\). Find the values of \(P\) and \(R\).

Question 3:
AnswerMarks Guidance
AnswerMarks Guidance
\(P/16\) or \(P/25\) seenB1 Use of Driving force \(= P/v\)
\(P/16 - R = 1500(0.3875)\) or \(P/25 - R = 1500(0.2)\)M1 Attempt to use N2L once, can be with \(D\) at this stage
\(P/16 - R = 1500(0.3875)\) and \(P/25 - R = 1500(0.2)\)A1 Both equations correct, may have consistent wrong sign with \(R\)
M1Attempt to solve for \(P\) or \(R\)
\(P = 12\,500\)A1 Allow 12.5 kW
\(R = 200\)A1 Allow if \(-\)ve, and justified why \(+\)ve (e.g. comment on direction)
## Question 3:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $P/16$ or $P/25$ seen | B1 | Use of Driving force $= P/v$ |
| $P/16 - R = 1500(0.3875)$ or $P/25 - R = 1500(0.2)$ | M1 | Attempt to use N2L once, can be with $D$ at this stage |
| $P/16 - R = 1500(0.3875)$ and $P/25 - R = 1500(0.2)$ | A1 | Both equations correct, may have consistent wrong sign with $R$ |
| | M1 | Attempt to solve for $P$ or $R$ |
| $P = 12\,500$ | A1 | Allow 12.5 kW |
| $R = 200$ | A1 | Allow if $-$ve, and justified why $+$ve (e.g. comment on direction) |

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3 A car of mass 1500 kg travels along a straight horizontal road with its engine working at a constant rate of $P \mathrm {~W}$. There is a constant resistance to motion of $R \mathrm {~N}$. Points $A$ and $B$ are on the road. At point $A$ the car's speed is $16 \mathrm {~ms} ^ { - 1 }$ and its acceleration is $0.3875 \mathrm {~ms} ^ { - 2 }$. At point $B$ the car's speed is $25 \mathrm {~ms} ^ { - 1 }$ and its acceleration is $0.2 \mathrm {~ms} ^ { - 2 }$. Find the values of $P$ and $R$.

\hfill \mbox{\textit{OCR M2 2015 Q3 [6]}}