AQA M2 2013 January — Question 5 7 marks

Exam BoardAQA
ModuleM2 (Mechanics 2)
Year2013
SessionJanuary
Marks7
PaperDownload PDF ↗
TopicVariable Force
TypeAir resistance with other powers
DifficultyStandard +0.8 This M2 question requires setting up and solving a differential equation with a non-standard fractional power (v^(1/3)) for resistance, then manipulating the result to match a given form with fractional exponents. While the method is standard (F=ma, separate variables, integrate), the algebraic manipulation with fractional powers is more demanding than typical M2 resistance problems which usually use v or v^2.
Spec1.08k Separable differential equations: dy/dx = f(x)g(y)6.06a Variable force: dv/dt or v*dv/dx methods

5 A particle, of mass 12 kg , is moving along a straight horizontal line. At time \(t\) seconds, the particle has speed \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\). As the particle moves, it experiences a resistance force of magnitude \(4 v ^ { \frac { 1 } { 3 } }\). No other horizontal force acts on the particle. The initial speed of the particle is \(8 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  1. Show that $$v = \left( 4 - \frac { 2 } { 9 } t \right) ^ { \frac { 3 } { 2 } }$$
  2. Find the value of \(t\) when the particle comes to rest.

5 A particle, of mass 12 kg , is moving along a straight horizontal line. At time $t$ seconds, the particle has speed $v \mathrm {~m} \mathrm {~s} ^ { - 1 }$. As the particle moves, it experiences a resistance force of magnitude $4 v ^ { \frac { 1 } { 3 } }$. No other horizontal force acts on the particle.

The initial speed of the particle is $8 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item Show that

$$v = \left( 4 - \frac { 2 } { 9 } t \right) ^ { \frac { 3 } { 2 } }$$
\item Find the value of $t$ when the particle comes to rest.
\end{enumerate}

\hfill \mbox{\textit{AQA M2 2013 Q5 [7]}}