CAIE P2 2019 November — Question 1 5 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2019
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSolve |linear| < |linear|
DifficultyStandard +0.3 This is a straightforward modulus inequality requiring squaring both sides to eliminate the modulus signs, leading to a simple linear inequality. Part (ii) adds a logarithmic substitution but is routine once part (i) is solved. Slightly above average due to the two-part structure and logarithmic application, but still a standard textbook exercise.
Spec1.02l Modulus function: notation, relations, equations and inequalities

1
  1. Solve the inequality \(| 2 x - 7 | < | 2 x - 9 |\).
  2. Hence find the largest integer \(n\) satisfying the inequality \(| 2 \ln n - 7 | < | 2 \ln n - 9 |\).

Question 1(i):
AnswerMarks Guidance
AnswerMarks Guidance
State or imply non-modular inequality \((2x-7)^2 < (2x-9)^2\) or corresponding equation or linear equation (with signs of \(2x\) different)M1
Obtain critical value 4A1
State \(x < 4\) onlyA1
Total3
Question 1(ii):
AnswerMarks Guidance
AnswerMarks Guidance
Attempt to find \(n\) from \(\ln n =\) *their* critical value from part (i)M1
Obtain or imply \(n < e^4\) and hence 54A1
Total2
## Question 1(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| State or imply non-modular inequality $(2x-7)^2 < (2x-9)^2$ or corresponding equation or linear equation (with signs of $2x$ different) | M1 | |
| Obtain critical value 4 | A1 | |
| State $x < 4$ only | A1 | |
| **Total** | **3** | |

## Question 1(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Attempt to find $n$ from $\ln n =$ *their* critical value from part (i) | M1 | |
| Obtain or imply $n < e^4$ and hence 54 | A1 | |
| **Total** | **2** | |
1 (i) Solve the inequality $| 2 x - 7 | < | 2 x - 9 |$.\\

(ii) Hence find the largest integer $n$ satisfying the inequality $| 2 \ln n - 7 | < | 2 \ln n - 9 |$.\\

\hfill \mbox{\textit{CAIE P2 2019 Q1 [5]}}