5 The velocity, \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\), of a particle moving along a straight line is given by
$$v = 3 t ^ { 2 } - 12 t + 14$$
where \(t\) is the time in seconds.
- Find an expression for the acceleration of the particle at time \(t\).
- Find the displacement of the particle from its position when \(t = 1\) to its position when \(t = 3\).
- You are given that \(v\) is always positive. Explain how this tells you that the distance travelled by the particle between \(t = 1\) and \(t = 3\) has the same value as the displacement between these times.
[0pt]
[2]