Edexcel M1 — Question 1 8 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors Introduction & 2D
TypeNewton's second law with vector forces (find acceleration or force)
DifficultyModerate -0.8 This is a straightforward M1 mechanics question requiring basic vector manipulation and Newton's second law. Part (a) uses Pythagoras to find λ from the given speed, and part (b) applies F=ma with constant acceleration to find the force vector. Both parts involve routine calculations with no problem-solving insight required, making it easier than average A-level questions.
Spec1.10c Magnitude and direction: of vectors1.10d Vector operations: addition and scalar multiplication3.03d Newton's second law: 2D vectors3.03f Weight: W=mg

  1. At time \(t = 0\), a particle of mass 2 kg has velocity \(( 8 \mathbf { i } + \lambda \mathbf { j } ) \mathrm { ms } ^ { - 1 }\) where \(\mathbf { i }\) and \(\mathbf { j }\) are horizontal perpendicular unit vectors and \(\lambda > 0\).
Given that the speed of the particle at time \(t = 0\) is \(17 \mathrm {~m} \mathrm {~s} ^ { - 1 }\),
  1. find the value of \(\lambda\). The particle experiences a constant retarding force \(\mathbf { F }\) so that when \(t = 5\), it has velocity \(( 3 \mathbf { i } + 5 \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 1 }\).
  2. Show that \(\mathbf { F }\) can be written in the form \(\mu ( \mathbf { i } + 2 \mathbf { j } ) \mathrm { N }\) where \(\mu\) is a constant which you should find.
    (5 marks)

Part (a)
AnswerMarks
Speed = 17 = mag. of vel. = \(\sqrt{8^2 + \lambda^2}\)M1
\(\lambda^2 = 289 - 64 = 225; \lambda > 0\) so \(\lambda = 15\)M1 A1
Part (b)
AnswerMarks Guidance
\(a = \frac{\Delta v}{t} = \frac{1}{2}[(3\mathbf{i} + 5\mathbf{j}) - (8\mathbf{i} + 15\mathbf{j})] = \mathbf{i} - 2\mathbf{j}\)M2 A1
\(\mathbf{F} = m\mathbf{a} = 2(\mathbf{i} - 2\mathbf{j}) = 2\mathbf{i} + 2\mathbf{j}\) so \(\mu = -2\)M1 A1 (8)
**Part (a)**
Speed = 17 = mag. of vel. = $\sqrt{8^2 + \lambda^2}$ | M1 | 
$\lambda^2 = 289 - 64 = 225; \lambda > 0$ so $\lambda = 15$ | M1 A1 |

**Part (b)**
$a = \frac{\Delta v}{t} = \frac{1}{2}[(3\mathbf{i} + 5\mathbf{j}) - (8\mathbf{i} + 15\mathbf{j})] = \mathbf{i} - 2\mathbf{j}$ | M2 A1 |
$\mathbf{F} = m\mathbf{a} = 2(\mathbf{i} - 2\mathbf{j}) = 2\mathbf{i} + 2\mathbf{j}$ so $\mu = -2$ | M1 A1 | (8)
\begin{enumerate}
  \item At time $t = 0$, a particle of mass 2 kg has velocity $( 8 \mathbf { i } + \lambda \mathbf { j } ) \mathrm { ms } ^ { - 1 }$ where $\mathbf { i }$ and $\mathbf { j }$ are horizontal perpendicular unit vectors and $\lambda > 0$.
\end{enumerate}

Given that the speed of the particle at time $t = 0$ is $17 \mathrm {~m} \mathrm {~s} ^ { - 1 }$,\\
(a) find the value of $\lambda$.

The particle experiences a constant retarding force $\mathbf { F }$ so that when $t = 5$, it has velocity $( 3 \mathbf { i } + 5 \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 1 }$.\\
(b) Show that $\mathbf { F }$ can be written in the form $\mu ( \mathbf { i } + 2 \mathbf { j } ) \mathrm { N }$ where $\mu$ is a constant which you should find.\\
(5 marks)\\

\hfill \mbox{\textit{Edexcel M1  Q1 [8]}}