Edexcel M1 — Question 6 10 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSUVAT in 2D & Gravity
TypeVertical projection: time at height
DifficultyModerate -0.3 This is a straightforward two-part SUVAT question with vertical motion under gravity. Part (a) requires finding maximum height using v²=u²+2as (standard technique), and part (b) requires solving a quadratic equation for times when height equals 2m. Both are routine M1 applications with no conceptual challenges, making it slightly easier than average.
Spec3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form

6. A boy kicks a football vertically upwards from a height of 0.6 m above the ground with a speed of \(10.5 \mathrm {~ms} ^ { - 1 }\). The ball is modelled as a particle and air resistance is ignored.
  1. Find the greatest height above the ground reached by the ball.
  2. Calculate the length of time for which the ball is more than 2 m above the ground.

AnswerMarks Guidance
(a) \(u = 10.5, v = 0, a = -g\) use \(v^2 = u^2 + 2as\)M1
\(0 = 110.25 - 19.6s \Rightarrow s = 5.625\)M1 A1
ball starts from 0.6 m, so it reaches 6.225 m above ground levelA1
(b) \(s = 2 - 0.6 = 1.4, u = 10.5, a = -g\), use \(s = ut + \frac{1}{2}at^2\)M1
\(10.5t - 4.9t^2 > 1.4\) i.e. \(7t^2 - 15t + 2 < 0\)M1 A1
\((7t - 1)(t - 2) < 0\) leading to \(\frac{1}{7} < t < 2\)M1 A1
ball is above ground for \(\frac{13}{7}\) (≈ 1.86) secondsA1 (10 marks)
**(a)** $u = 10.5, v = 0, a = -g$ use $v^2 = u^2 + 2as$ | M1 |
$0 = 110.25 - 19.6s \Rightarrow s = 5.625$ | M1 A1 |
ball starts from 0.6 m, so it reaches 6.225 m above ground level | A1 |

**(b)** $s = 2 - 0.6 = 1.4, u = 10.5, a = -g$, use $s = ut + \frac{1}{2}at^2$ | M1 |
$10.5t - 4.9t^2 > 1.4$ i.e. $7t^2 - 15t + 2 < 0$ | M1 A1 |
$(7t - 1)(t - 2) < 0$ leading to $\frac{1}{7} < t < 2$ | M1 A1 |
ball is above ground for $\frac{13}{7}$ (≈ 1.86) seconds | A1 | (10 marks)
6. A boy kicks a football vertically upwards from a height of 0.6 m above the ground with a speed of $10.5 \mathrm {~ms} ^ { - 1 }$. The ball is modelled as a particle and air resistance is ignored.
\begin{enumerate}[label=(\alph*)]
\item Find the greatest height above the ground reached by the ball.
\item Calculate the length of time for which the ball is more than 2 m above the ground.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q6 [10]}}