CAIE P2 2018 November — Question 4 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2018
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeRearrange to iterative form
DifficultyModerate -0.3 This is a straightforward fixed point iteration question requiring routine algebraic manipulation to rearrange x⁴ + 2x³ + 2x² - 12x - 32 = 0 into the form x = ∛(p + qx). The factor theorem part is basic substitution, and the iteration itself is mechanical application of a formula. While it involves multiple parts, each step follows standard A-level procedures without requiring novel insight or complex problem-solving.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.09a Sign change methods: locate roots1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

4 \includegraphics[max width=\textwidth, alt={}, center]{6bf7ba66-8362-4ac0-8e5c-3f88a3ccdf86-06_652_789_260_676} The diagram shows the curve with equation $$y = x ^ { 4 } + 2 x ^ { 3 } + 2 x ^ { 2 } - 12 x - 32$$ The curve crosses the \(x\)-axis at points with coordinates \(( \alpha , 0 )\) and \(( \beta , 0 )\).
  1. Use the factor theorem to show that \(( x + 2 )\) is a factor of $$x ^ { 4 } + 2 x ^ { 3 } + 2 x ^ { 2 } - 12 x - 32$$
  2. Show that \(\beta\) satisfies an equation of the form \(x = \sqrt [ 3 ] { } ( p + q x )\), and state the values of \(p\) and \(q\). [3]
  3. Use an iterative formula based on the equation in part (ii) to find the value of \(\beta\) correct to 4 significant figures. Give the result of each iteration to 6 significant figures.

Question 4(i):
AnswerMarks Guidance
AnswerMarks Guidance
Substitute \(-2\) and simplifyM1
Obtain \(16 - 16 + 8 + 24 - 32\) and hence zero and concludeA1 AG; necessary detail needed
Question 4(ii):
AnswerMarks Guidance
AnswerMarks Guidance
Attempt division by \(x+2\) to reach at least partial quotient \(x^3 + kx\) or use of identity or inspectionM1
Obtain \(x^3 + 2x - 16\)A1
Equate to zero and obtain \(x = \sqrt[3]{16-2x}\)A1
Question 4(iii):
AnswerMarks Guidance
AnswerMarks Guidance
Use iteration process correctly at least onceM1
Obtain final answer 2.256A1
Show sufficient iterations to 6 sf to justify answer or show a sign change in the interval \((2.2555, 2.2565)\)A1
## Question 4(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Substitute $-2$ and simplify | M1 | |
| Obtain $16 - 16 + 8 + 24 - 32$ and hence zero and conclude | A1 | AG; necessary detail needed |

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## Question 4(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Attempt division by $x+2$ to reach at least partial quotient $x^3 + kx$ or use of identity or inspection | M1 | |
| Obtain $x^3 + 2x - 16$ | A1 | |
| Equate to zero and obtain $x = \sqrt[3]{16-2x}$ | A1 | |

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## Question 4(iii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Use iteration process correctly at least once | M1 | |
| Obtain final answer 2.256 | A1 | |
| Show sufficient iterations to 6 sf to justify answer or show a sign change in the interval $(2.2555, 2.2565)$ | A1 | |

---
4\\
\includegraphics[max width=\textwidth, alt={}, center]{6bf7ba66-8362-4ac0-8e5c-3f88a3ccdf86-06_652_789_260_676}

The diagram shows the curve with equation

$$y = x ^ { 4 } + 2 x ^ { 3 } + 2 x ^ { 2 } - 12 x - 32$$

The curve crosses the $x$-axis at points with coordinates $( \alpha , 0 )$ and $( \beta , 0 )$.\\
(i) Use the factor theorem to show that $( x + 2 )$ is a factor of

$$x ^ { 4 } + 2 x ^ { 3 } + 2 x ^ { 2 } - 12 x - 32$$

(ii) Show that $\beta$ satisfies an equation of the form $x = \sqrt [ 3 ] { } ( p + q x )$, and state the values of $p$ and $q$. [3]\\

(iii) Use an iterative formula based on the equation in part (ii) to find the value of $\beta$ correct to 4 significant figures. Give the result of each iteration to 6 significant figures.\\

\hfill \mbox{\textit{CAIE P2 2018 Q4 [8]}}