Edexcel S2 — Question 5 12 marks

Exam BoardEdexcel
ModuleS2 (Statistics 2)
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicApproximating Binomial to Normal Distribution
TypeExact binomial then normal approximation (same context, different n)
DifficultyStandard +0.3 This is a straightforward S2 question requiring basic binomial probability calculations in parts (a) and (b), then a standard normal approximation to binomial in part (c). The setup is clear, the probability is given (p=6/15=0.4 for red), and part (c) follows a textbook procedure (check np>5, apply continuity correction, standardize). Slightly above average difficulty only because it combines multiple techniques across three parts, but each step is routine for S2 students.
Spec2.04b Binomial distribution: as model B(n,p)2.04c Calculate binomial probabilities2.04d Normal approximation to binomial

  1. Lupin seeds are sold in packets of 15 . On average, 9 seeds in a packet are green and 6 are red. Find, to 2 decimal places, the probability that in any particular packet there are
    1. less than 2 red seeds,
    2. more red than green seeds.
    The seeds from 10 packets are then combined together.
  2. Use a suitable approximation to find the probability that the total number of green seeds is more than 100 .

AnswerMarks Guidance
(a) \(R \sim B(15, 0.4)\); \(P(R < 2) = P(R \leq 1) = 0.0052\)B1 M1 A1
(b) \(P(R \geq 8) = 1 - P(R \leq 7) = 1 - 0.7869 = 0.213\)M1 A1
(c) Number of greens is \(G \sim B(150, 0.6) \approx N(90, 36)\)M1 A1
\(P(G > 100.5) = P(Z > 10.5/6) = P(Z > 1.75) = 0.0401\)M1 A1 M1 A1 A1 Total: 12 marks
(a) $R \sim B(15, 0.4)$; $P(R < 2) = P(R \leq 1) = 0.0052$ | B1 M1 A1 |

(b) $P(R \geq 8) = 1 - P(R \leq 7) = 1 - 0.7869 = 0.213$ | M1 A1 |

(c) Number of greens is $G \sim B(150, 0.6) \approx N(90, 36)$ | M1 A1 |

$P(G > 100.5) = P(Z > 10.5/6) = P(Z > 1.75) = 0.0401$ | M1 A1 M1 A1 A1 | Total: 12 marks
\begin{enumerate}
  \item Lupin seeds are sold in packets of 15 . On average, 9 seeds in a packet are green and 6 are red. Find, to 2 decimal places, the probability that in any particular packet there are\\
(a) less than 2 red seeds,\\
(b) more red than green seeds.
\end{enumerate}

The seeds from 10 packets are then combined together.\\
(c) Use a suitable approximation to find the probability that the total number of green seeds is more than 100 .\\

\hfill \mbox{\textit{Edexcel S2  Q5 [12]}}