Edexcel S1 — Question 3 12 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNormal Distribution
TypeIndependent probability calculations
DifficultyStandard +0.3 This is a straightforward S1 normal distribution question requiring standard z-score calculations and independent probability multiplication. Part (d) adds slight conceptual depth by asking for comparison reasoning about combined distributions, but overall this is a routine textbook exercise with no novel problem-solving required.
Spec2.04e Normal distribution: as model N(mu, sigma^2)2.04f Find normal probabilities: Z transformation5.04a Linear combinations: E(aX+bY), Var(aX+bY)

3. A study was made of the heights of boys of different ages in Lancashire. The study concluded that the heights of 13 year-old boys are normally distributed with a mean of 156 cm and a variance of \(73 \mathrm {~cm} ^ { 2 }\). Find the probability that a 13 year-old boy chosen at random will be
  1. more than 165 cm tall,
  2. between 156 and 165 cm tall. The study also concluded that the heights of 14 year-old boys are normally distributed with a mean of 160 cm and a variance of \(79 \mathrm {~cm} ^ { 2 }\). One 13 year-old and one 14 year-old boy are chosen at random.
  3. Find the probability that both boys are more than 165 cm tall.
  4. State, with a reason, whether the probability that the combined height of the two boys is more than 330 cm is more or less than your answer to part (c).
    (2 marks)

AnswerMarks
(a) \(P(Z > \frac{165-156}{\sqrt{73}}) = P(Z > 1.05) = 0.1469\)M2 A1
(b) \(1 - (0.5 + 0.1469) = 0.3531\)M1 A1
(c) \(P(14yo > 165) = P(Z > \frac{165-160}{\sqrt{79}}) = P(Z > 0.56) = 0.2877\); \(P(\text{both} > 165) = 0.1469 \times 0.2877 = 0.0423\) (3sf)M2 A1 M1 A1
(d) more as e.g. answer to (c) satisfies condition but can also have one less than 165 if the other is sufficiently over 165B2
(12)
**(a)** $P(Z > \frac{165-156}{\sqrt{73}}) = P(Z > 1.05) = 0.1469$ | M2 A1 |

**(b)** $1 - (0.5 + 0.1469) = 0.3531$ | M1 A1 |

**(c)** $P(14yo > 165) = P(Z > \frac{165-160}{\sqrt{79}}) = P(Z > 0.56) = 0.2877$; $P(\text{both} > 165) = 0.1469 \times 0.2877 = 0.0423$ (3sf) | M2 A1 M1 A1 |

**(d)** more as e.g. answer to (c) satisfies condition but can also have one less than 165 if the other is sufficiently over 165 | B2 |

| | | (12) |

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3. A study was made of the heights of boys of different ages in Lancashire.

The study concluded that the heights of 13 year-old boys are normally distributed with a mean of 156 cm and a variance of $73 \mathrm {~cm} ^ { 2 }$.

Find the probability that a 13 year-old boy chosen at random will be
\begin{enumerate}[label=(\alph*)]
\item more than 165 cm tall,
\item between 156 and 165 cm tall.

The study also concluded that the heights of 14 year-old boys are normally distributed with a mean of 160 cm and a variance of $79 \mathrm {~cm} ^ { 2 }$.

One 13 year-old and one 14 year-old boy are chosen at random.
\item Find the probability that both boys are more than 165 cm tall.
\item State, with a reason, whether the probability that the combined height of the two boys is more than 330 cm is more or less than your answer to part (c).\\
(2 marks)
\end{enumerate}

\hfill \mbox{\textit{Edexcel S1  Q3 [12]}}