Edexcel S1 — Question 4 10 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear regression
TypeCalculate y on x from summary statistics
DifficultyModerate -0.8 This is a straightforward application of standard regression formulas (b = S_vc/S_vv, a = ȳ - bx̄) with simple arithmetic, followed by routine interpretation and substitution. All steps are mechanical with no problem-solving or conceptual challenge beyond basic recall of the regression line method.
Spec5.09a Dependent/independent variables5.09b Least squares regression: concepts5.09c Calculate regression line5.09d Linear coding: effect on regression

4. An internet service provider runs a series of television adverts at weekly intervals. To investigate the effectiveness of the adverts the company recorded the viewing figures in millions, \(v\), for the programme in which the advert was shown, and the number of new customers, \(c\), who signed up for their service the next day. The results are summarised as follows. $$\bar { v } = 4.92 , \quad \bar { c } = 104.4 , \quad S _ { v c } = 594.05 , \quad S _ { v v } = 85.44 .$$
  1. Calculate the equation of the regression line of \(c\) on \(v\) in the form \(c = a + b v\).
  2. Give an interpretation of the constants \(a\) and \(b\) in this context.
  3. Estimate the number of customers that will sign up with the company the day after an advert is shown during a programme watched by 3.7 million viewers.
  4. State two other factors besides viewing figures that will affect the success of an advert in gaining new customers for the company.

AnswerMarks Guidance
(a) \(b = \frac{594.05}{85.44} = 6.953\)M1
\(a = 104.4 - (6.953 \times 4.92) = 70.192\)M1
\(c = 70.2 + 6.95y\)M1 A1
(b) \(a\) = no. of sign-ups without an advertB1
\(b\) = no. of extra sign-ups per million viewers of advertB1
(c) \(70.192 + (6.953 \times 3.7) = 95.92 \therefore 96\)M1 A1
(d) e.g. type of programme; length of advertB2 (10 marks total)
(a) $b = \frac{594.05}{85.44} = 6.953$ | M1 |

$a = 104.4 - (6.953 \times 4.92) = 70.192$ | M1 |

$c = 70.2 + 6.95y$ | M1 A1 |

(b) $a$ = no. of sign-ups without an advert | B1 |

$b$ = no. of extra sign-ups per million viewers of advert | B1 |

(c) $70.192 + (6.953 \times 3.7) = 95.92 \therefore 96$ | M1 A1 |

(d) e.g. type of programme; length of advert | B2 | (10 marks total)
4. An internet service provider runs a series of television adverts at weekly intervals. To investigate the effectiveness of the adverts the company recorded the viewing figures in millions, $v$, for the programme in which the advert was shown, and the number of new customers, $c$, who signed up for their service the next day.

The results are summarised as follows.

$$\bar { v } = 4.92 , \quad \bar { c } = 104.4 , \quad S _ { v c } = 594.05 , \quad S _ { v v } = 85.44 .$$
\begin{enumerate}[label=(\alph*)]
\item Calculate the equation of the regression line of $c$ on $v$ in the form $c = a + b v$.
\item Give an interpretation of the constants $a$ and $b$ in this context.
\item Estimate the number of customers that will sign up with the company the day after an advert is shown during a programme watched by 3.7 million viewers.
\item State two other factors besides viewing figures that will affect the success of an advert in gaining new customers for the company.
\end{enumerate}

\hfill \mbox{\textit{Edexcel S1  Q4 [10]}}