AQA S1 2008 January — Question 1 12 marks

Exam BoardAQA
ModuleS1 (Statistics 1)
Year2008
SessionJanuary
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNormal Distribution
TypeProbability calculation plus find unknown boundary
DifficultyModerate -0.8 This is a straightforward application of normal distribution with standard z-score calculations and inverse normal lookup. Part (a) involves three routine probability calculations using tables, while part (b) requires finding a mean given a probability—all standard S1 techniques with no conceptual challenges or multi-step reasoning required.
Spec2.04e Normal distribution: as model N(mu, sigma^2)2.04f Find normal probabilities: Z transformation

1 In large-scale tree-felling operations, a machine cuts down trees, strips off the branches and then cuts the trunks into logs of length \(X\) metres for transporting to a sawmill. It may be assumed that values of \(X\) are normally distributed with mean \(\mu\) and standard deviation 0.16 , where \(\mu\) can be set to a specific value.
  1. Given that \(\mu\) is set to 3.3 , determine:
    1. \(\mathrm { P } ( X < 3.5 )\);
    2. \(\mathrm { P } ( X > 3.0 )\);
    3. \(\mathrm { P } ( 3.0 < X < 3.5 )\).
  2. The sawmill now requires a batch of logs such that there is a probability of 0.025 that any given log will have a length less than 3.1 metres. Determine, to two decimal places, the new value of \(\mu\).

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1 | 79 | 82

This doesn't appear to be a full mark scheme with marking annotations (M1, A1, B1, etc) and guidance notes that you mentioned in your instructions. 

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1 In large-scale tree-felling operations, a machine cuts down trees, strips off the branches and then cuts the trunks into logs of length $X$ metres for transporting to a sawmill.

It may be assumed that values of $X$ are normally distributed with mean $\mu$ and standard deviation 0.16 , where $\mu$ can be set to a specific value.
\begin{enumerate}[label=(\alph*)]
\item Given that $\mu$ is set to 3.3 , determine:
\begin{enumerate}[label=(\roman*)]
\item $\mathrm { P } ( X < 3.5 )$;
\item $\mathrm { P } ( X > 3.0 )$;
\item $\mathrm { P } ( 3.0 < X < 3.5 )$.
\end{enumerate}\item The sawmill now requires a batch of logs such that there is a probability of 0.025 that any given log will have a length less than 3.1 metres.

Determine, to two decimal places, the new value of $\mu$.
\end{enumerate}

\hfill \mbox{\textit{AQA S1 2008 Q1 [12]}}