Edexcel C3 — Question 7 12 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSketch y=|f(x)| or y=f(|x|) for non-linear f(x) and solve
DifficultyStandard +0.3 This question involves standard transformations of modulus graphs with a quadratic function, finding composite functions, and solving a straightforward equation. While it requires understanding of modulus transformations and function composition, these are routine C3 techniques with no novel problem-solving required. The multi-part structure and algebraic manipulation with parameters make it slightly above average difficulty, but all steps follow standard procedures.
Spec1.02c Simultaneous equations: two variables by elimination and substitution1.02l Modulus function: notation, relations, equations and inequalities1.02u Functions: definition and vocabulary (domain, range, mapping)1.02w Graph transformations: simple transformations of f(x)

7. The function f is defined by $$\mathrm { f } ( x ) \equiv x ^ { 2 } - 2 a x , \quad x \in \mathbb { R } ,$$ where \(a\) is a positive constant.
  1. Showing the coordinates of any points where each graph meets the axes, sketch on separate diagrams the graphs of
    1. \(\quad y = | \mathrm { f } ( x ) |\),
    2. \(y = \mathrm { f } ( | x | )\). The function g is defined by $$\mathrm { g } ( x ) \equiv 3 a x , \quad x \in \mathbb { R } .$$
  2. Find fg(a) in terms of \(a\).
  3. Solve the equation $$\operatorname { gf } ( x ) = 9 a ^ { 3 }$$

(a)
AnswerMarks
(i) Graph with minimum at \((0,0)\) and \((2a,0)\)B3
(ii) Graph with maxima at \((-2a,0)\) and \((2a,0)\), minimum at \((0,0)\)B3
(b)
AnswerMarks
\(= f(3a^2) = 9a^4 - 6a^3\)M1 A1
(c)
AnswerMarks Guidance
\(g(x) = 3a(x^2-2ax)\)M1
\(\therefore 3a(x^2-2ax) = 9a^3\)
\(x^2 - 2ax - 3a^2 = 0\)A1
\((x+a)(x-3a) = 0\)M1
\(x = -a, 3a\)A1 (12)
**(a)**
(i) Graph with minimum at $(0,0)$ and $(2a,0)$ | B3 |
(ii) Graph with maxima at $(-2a,0)$ and $(2a,0)$, minimum at $(0,0)$ | B3 |

**(b)**
$= f(3a^2) = 9a^4 - 6a^3$ | M1 A1 |

**(c)**
$g(x) = 3a(x^2-2ax)$ | M1 |
$\therefore 3a(x^2-2ax) = 9a^3$ | |
$x^2 - 2ax - 3a^2 = 0$ | A1 |
$(x+a)(x-3a) = 0$ | M1 |
$x = -a, 3a$ | A1 | (12)

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7. The function f is defined by

$$\mathrm { f } ( x ) \equiv x ^ { 2 } - 2 a x , \quad x \in \mathbb { R } ,$$

where $a$ is a positive constant.
\begin{enumerate}[label=(\alph*)]
\item Showing the coordinates of any points where each graph meets the axes, sketch on separate diagrams the graphs of
\begin{enumerate}[label=(\roman*)]
\item $\quad y = | \mathrm { f } ( x ) |$,
\item $y = \mathrm { f } ( | x | )$.

The function g is defined by

$$\mathrm { g } ( x ) \equiv 3 a x , \quad x \in \mathbb { R } .$$
\end{enumerate}\item Find fg(a) in terms of $a$.
\item Solve the equation

$$\operatorname { gf } ( x ) = 9 a ^ { 3 }$$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3  Q7 [12]}}