Edexcel C3 — Question 1 6 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeSolve equation with reciprocal functions
DifficultyStandard +0.8 This question requires converting cosec to 1/sin, forming a quadratic in sin θ or cos θ, solving it, and finding solutions in a restricted domain. It combines reciprocal trig functions with equation solving and requires careful algebraic manipulation, making it moderately challenging but still within standard C3 scope.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05o Trigonometric equations: solve in given intervals

  1. Solve the equation
$$3 \operatorname { cosec } \theta ^ { \circ } + 8 \cos \theta ^ { \circ } = 0$$ for \(\theta\) in the interval \(0 \leq \theta \leq 180\), giving your answers to 1 decimal place.

AnswerMarks Guidance
\(\frac{3}{\sin\theta} = -8\cos\theta\)M1
\(3 = -8\sin\theta\cos\theta = -4\sin 2\theta\)M1
\(\sin 2\theta = -\frac{3}{4}\)A1
\(2\theta = 180 + 48.590, 360 - 48.590 = 228.590, 311.410\)M1
\(\theta = 114.3, 155.7\) (1dp)A2 (6)
$\frac{3}{\sin\theta} = -8\cos\theta$ | M1 |
$3 = -8\sin\theta\cos\theta = -4\sin 2\theta$ | M1 |
$\sin 2\theta = -\frac{3}{4}$ | A1 |
$2\theta = 180 + 48.590, 360 - 48.590 = 228.590, 311.410$ | M1 |
$\theta = 114.3, 155.7$ (1dp) | A2 | (6)
\begin{enumerate}
  \item Solve the equation
\end{enumerate}

$$3 \operatorname { cosec } \theta ^ { \circ } + 8 \cos \theta ^ { \circ } = 0$$

for $\theta$ in the interval $0 \leq \theta \leq 180$, giving your answers to 1 decimal place.\\

\hfill \mbox{\textit{Edexcel C3  Q1 [6]}}