AQA C3 2010 June — Question 2 10 marks

Exam BoardAQA
ModuleC3 (Core Mathematics 3)
Year2010
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeSketch reciprocal function graphs
DifficultyModerate -0.3 This question tests standard knowledge of reciprocal trig functions with routine transformations. Part (a)(i) is trivial recall (sec 0° = 1), part (a)(ii) requires sketching a transformed graph using known techniques (period halving and absolute value), and parts (b)-(c) involve solving sec equations by converting to cos, which is a standard textbook exercise. While multi-part, each component is straightforward application of learned techniques without requiring problem-solving insight.
Spec1.02w Graph transformations: simple transformations of f(x)1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05o Trigonometric equations: solve in given intervals

2
  1. The diagram shows the graph of \(y = \sec x\) for \(0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }\).
    1. The point \(A\) on the curve is where \(x = 0\). State the \(y\)-coordinate of \(A\).
    2. Sketch, on the axes given on page 3, the graph of \(y = | \sec 2 x |\) for \(0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }\).
  2. Solve the equation \(\sec x = 2\), giving all values of \(x\) in degrees in the interval \(0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }\).
  3. Solve the equation \(\left| \sec \left( 2 x - 10 ^ { \circ } \right) \right| = 2\), giving all values of \(x\) in degrees in the interval \(0 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }\).

Question 2:
Part (a)(i)
AnswerMarks
\(y = 1\)B1
Part (a)(ii)
AnswerMarks Guidance
Graph of \(\sec 2x \): period \(90°\), correct shape with cusps on \(x\)-axis, amplitude correct, all correct
Part (b)
AnswerMarks Guidance
\(\sec x = 2 \Rightarrow \cos x = \frac{1}{2} \Rightarrow x = 60°, 300°\)M1 A1 M1 for \(\cos x = \frac{1}{2}\)
Part (c)
AnswerMarks Guidance
\(\sec(2x-10°) = 2 \Rightarrow \sec(2x-10°) = \pm 2 \Rightarrow \cos(2x-10°) = \pm\frac{1}{2}\)
\(2x - 10° = 60°, 120°, 240°, 300°\) (and negatives)M1
\(x = 35°, 65°, 125°, 155°\)A1 A1 A1 for each correct pair
# Question 2:

## Part (a)(i)
| $y = 1$ | B1 | |

## Part (a)(ii)
| Graph of $|\sec 2x|$: period $90°$, correct shape with cusps on $x$-axis, amplitude correct, all correct | B1 B1 B1 | B1 shape/period, B1 cusps touching axis, B1 fully correct |

## Part (b)
| $\sec x = 2 \Rightarrow \cos x = \frac{1}{2} \Rightarrow x = 60°, 300°$ | M1 A1 | M1 for $\cos x = \frac{1}{2}$ |

## Part (c)
| $|\sec(2x-10°)| = 2 \Rightarrow \sec(2x-10°) = \pm 2 \Rightarrow \cos(2x-10°) = \pm\frac{1}{2}$ | M1 | |
| $2x - 10° = 60°, 120°, 240°, 300°$ (and negatives) | M1 | |
| $x = 35°, 65°, 125°, 155°$ | A1 A1 | A1 for each correct pair |

---
2
\begin{enumerate}[label=(\alph*)]
\item The diagram shows the graph of $y = \sec x$ for $0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }$.\\
\begin{tikzpicture}[>=stealth, scale=1]

  % --- Clipping region ---
  \clip (-0.8,-4.5) rectangle (10.8,4.8);

  % --- Axes ---
  \draw[->] (-0.5,0) -- (10.5,0) node[right] {$x$};
  \draw[->] (0,-4.3) -- (0,4.5) node[above] {$y$};
  \node[below left] at (0,0) {$O$};

  % Scaling: 90^\circ = 2.5 units on x-axis
  % x-ticks
  \draw (2.5,0.1) -- (2.5,-0.1) node[below] {$90^\circ$};
  \draw (5,0.1)   -- (5,-0.1)   node[below] {$180^\circ$};
  \draw (7.5,0.1) -- (7.5,-0.1) node[below] {$270^\circ$};
  \draw (10,0.1)  -- (10,-0.1)  node[below] {$360^\circ$};

  % y-tick at A = 1
  \draw (0.1,1) -- (-0.1,1) node[left] {$A$};

  % --- Dashed asymptotes at 90^\circ and 270^\circ ---
  \draw[dashed, thick, gray] (2.5,-4.3) -- (2.5,4.5);
  \draw[dashed, thick, gray] (7.5,-4.3) -- (7.5,4.5);

  % --- y = sec(x) ---
  % Branch 1: 0^\circ to ~88^\circ (sec > 0, going to +inf)
  \draw[thick, domain=0:88, samples=100]
    plot ({2.5*\x/90}, {1/cos(\x)});

  % Branch 2: ~92^\circ to ~268^\circ (sec < 0 in the middle, U-shape below)
  \draw[thick, domain=92:268, samples=150]
    plot ({2.5*\x/90}, {1/cos(\x)});

  % Branch 3: ~272^\circ to 360^\circ (sec > 0, coming from +inf)
  \draw[thick, domain=272:360, samples=100]
    plot ({2.5*\x/90}, {1/cos(\x)});

\end{tikzpicture}
\begin{enumerate}[label=(\roman*)]
\item The point $A$ on the curve is where $x = 0$. State the $y$-coordinate of $A$.
\item Sketch, on the axes given on page 3, the graph of $y = | \sec 2 x |$ for $0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }$.
\end{enumerate}\item Solve the equation $\sec x = 2$, giving all values of $x$ in degrees in the interval $0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }$.
\item Solve the equation $\left| \sec \left( 2 x - 10 ^ { \circ } \right) \right| = 2$, giving all values of $x$ in degrees in the interval $0 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }$.
\end{enumerate}

\hfill \mbox{\textit{AQA C3 2010 Q2 [10]}}