CAIE P2 2005 November — Question 5 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2005
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeRearrange to iterative form
DifficultyStandard +0.3 This is a straightforward fixed-point iteration question requiring standard techniques: sketching graphs to show uniqueness, verifying a root interval by substitution, algebraic rearrangement (trivial exponential manipulation), and applying a given iterative formula. All steps are routine with no novel insight required, making it slightly easier than average.
Spec1.02m Graphs of functions: difference between plotting and sketching1.06d Natural logarithm: ln(x) function and properties1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

5
  1. By sketching a suitable pair of graphs, show that there is only one value of \(x\) that is a root of the equation $$\frac { 1 } { x } = \ln x$$
  2. Verify by calculation that this root lies between 1 and 2 .
  3. Show that this root also satisfies the equation $$x = \mathrm { e } ^ { \frac { 1 } { x } }$$
  4. Use the iterative formula $$x _ { n + 1 } = \mathrm { e } ^ { \frac { 1 } { x _ { n } } }$$ with initial value \(x _ { 1 } = 1.8\), to determine this root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

AnswerMarks Guidance
(i) Make recognizable sketch of a relevant graph, e.g. \(y = 1/x\)B1
(ii) Sketch an appropriate second graph, e.g. \(y = \ln x\), correctly and justify the given statementB1 2
(iii) Consider the sign of \(x\) in \(x = 1\) and \(x = 2\), or equivalentM1
Complete the argument correctly with appropriate calculationsA1 2
(iii) Show that the given equation is equivalent to \(1/x = \ln x\), or vice versaB1 1
(iv) Use the iterative formula correctly at least onceM1
Obtain final answer 1.76A1
Show sufficient iterations to justify its accuracy to 2 d.p., or show there is a sign change in (1.755, 1.765)B1 3
(i) Make recognizable sketch of a relevant graph, e.g. $y = 1/x$ | B1 |

(ii) Sketch an appropriate second graph, e.g. $y = \ln x$, correctly and justify the given statement | B1 | 2

(iii) Consider the sign of $x$ in $x = 1$ and $x = 2$, or equivalent | M1 |
Complete the argument correctly with appropriate calculations | A1 | 2

(iii) Show that the given equation is equivalent to $1/x = \ln x$, or vice versa | B1 | 1

(iv) Use the iterative formula correctly at least once | M1 |
Obtain final answer 1.76 | A1 |
Show sufficient iterations to justify its accuracy to 2 d.p., or show there is a sign change in (1.755, 1.765) | B1 | 3
5 (i) By sketching a suitable pair of graphs, show that there is only one value of $x$ that is a root of the equation

$$\frac { 1 } { x } = \ln x$$

(ii) Verify by calculation that this root lies between 1 and 2 .\\
(iii) Show that this root also satisfies the equation

$$x = \mathrm { e } ^ { \frac { 1 } { x } }$$

(iv) Use the iterative formula

$$x _ { n + 1 } = \mathrm { e } ^ { \frac { 1 } { x _ { n } } }$$

with initial value $x _ { 1 } = 1.8$, to determine this root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

\hfill \mbox{\textit{CAIE P2 2005 Q5 [8]}}