AQA C1 2010 June — Question 3

Exam BoardAQA
ModuleC1 (Core Mathematics 1)
Year2010
SessionJune
TopicFactor & Remainder Theorem
TypeDirect remainder then factorise

3 The polynomial \(\mathrm { p } ( x )\) is given by $$\mathrm { p } ( x ) = x ^ { 3 } + 7 x ^ { 2 } + 7 x - 15$$
    1. Use the Factor Theorem to show that \(x + 3\) is a factor of \(\mathrm { p } ( x )\).
    2. Express \(\mathrm { p } ( x )\) as the product of three linear factors.
  1. Use the Remainder Theorem to find the remainder when \(\mathrm { p } ( x )\) is divided by \(x - 2\).
    1. Verify that \(\mathrm { p } ( - 1 ) < \mathrm { p } ( 0 )\).
    2. Sketch the curve with equation \(y = x ^ { 3 } + 7 x ^ { 2 } + 7 x - 15\), indicating the values where the curve crosses the coordinate axes.