AQA C1 2012 January — Question 2 10 marks

Exam BoardAQA
ModuleC1 (Core Mathematics 1)
Year2012
SessionJanuary
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCompleting the square and sketching
TypeSketch quadratic curve
DifficultyModerate -0.8 This is a routine multi-part question covering standard C1 quadratic techniques: factorising, sketching, completing the square, and transformations. All parts are textbook exercises requiring straightforward application of learned methods with no problem-solving or novel insight needed. Slightly easier than average due to the simple coefficients and step-by-step scaffolding.
Spec1.02d Quadratic functions: graphs and discriminant conditions1.02e Complete the square: quadratic polynomials and turning points1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02n Sketch curves: simple equations including polynomials1.02w Graph transformations: simple transformations of f(x)

2
  1. Factorise \(x ^ { 2 } - 4 x - 12\).
  2. Sketch the graph with equation \(y = x ^ { 2 } - 4 x - 12\), stating the values where the curve crosses the coordinate axes.
    1. Express \(x ^ { 2 } - 4 x - 12\) in the form \(( x - p ) ^ { 2 } - q\), where \(p\) and \(q\) are positive integers.
    2. Hence find the minimum value of \(x ^ { 2 } - 4 x - 12\).
  3. The curve with equation \(y = x ^ { 2 } - 4 x - 12\) is translated by the vector \(\left[ \begin{array} { r } - 3 \\ 2 \end{array} \right]\). Find an equation of the new curve. You need not simplify your answer.

Question 2:
Part (a)
AnswerMarks Guidance
WorkingMark Guidance
\((x-6)(x+2)\)B1 ISW for \(x=6, x=-2\) etc
Part (b)
AnswerMarks Guidance
WorkingMark Guidance
\(x = -2\), \(x = 6\)B1\(\checkmark\) Correct \(x\) values or FT 'their' factors (\(x\)-intercepts stated or marked on sketch); may be seen in (a)
\(y = -12\)B1 Stated or \(-12\) marked on sketch
\(\cup\)-shaped curveM1 Approximately
"Correct" shape in all 4 quadrants with minimum to right of \(y\)-axisA1
Part (c)(i)
AnswerMarks Guidance
WorkingMark Guidance
\((x-2)^2\)M1 \(p = 2\)
\((x-2)^2 - 16\)A1 \(p = 2\) and \(q = 16\)
Part (c)(ii)
AnswerMarks Guidance
WorkingMark Guidance
(Minimum value is) \(-16\)B1\(\checkmark\) FT 'their \(-q\)'
Part (d)
AnswerMarks Guidance
WorkingMark Guidance
Replacing each \(x\) by \(x+3\) OR adding 2 to their quadraticM1 In original equation or 'their' completed square or factorised form, or replacing \(y\) by \(y-2\)
\(y = [(x+3)^2 - 4(x+3) - 12] + 2\) or \(y = (x+1)^2 - 14\) or \(y = x^2 + 2x - 13\) or \(y - 2 = (x-3)(x+5)\)A1 OE any correct equation in \(x\) and \(y\) unsimplified
# Question 2:

## Part (a)
| Working | Mark | Guidance |
|---------|------|----------|
| $(x-6)(x+2)$ | B1 | ISW for $x=6, x=-2$ etc |

## Part (b)
| Working | Mark | Guidance |
|---------|------|----------|
| $x = -2$, $x = 6$ | B1$\checkmark$ | Correct $x$ values or FT 'their' factors ($x$-intercepts stated or marked on sketch); may be seen in (a) |
| $y = -12$ | B1 | Stated or $-12$ marked on sketch |
| $\cup$-shaped curve | M1 | Approximately |
| "Correct" shape in all 4 quadrants with minimum to right of $y$-axis | A1 | |

## Part (c)(i)
| Working | Mark | Guidance |
|---------|------|----------|
| $(x-2)^2$ | M1 | $p = 2$ |
| $(x-2)^2 - 16$ | A1 | $p = 2$ and $q = 16$ |

## Part (c)(ii)
| Working | Mark | Guidance |
|---------|------|----------|
| (Minimum value is) $-16$ | B1$\checkmark$ | FT 'their $-q$' |

## Part (d)
| Working | Mark | Guidance |
|---------|------|----------|
| Replacing each $x$ by $x+3$ **OR** adding 2 to their quadratic | M1 | In original equation or 'their' completed square or factorised form, or replacing $y$ by $y-2$ |
| $y = [(x+3)^2 - 4(x+3) - 12] + 2$ or $y = (x+1)^2 - 14$ or $y = x^2 + 2x - 13$ or $y - 2 = (x-3)(x+5)$ | A1 | OE any correct equation in $x$ and $y$ **unsimplified** |

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2
\begin{enumerate}[label=(\alph*)]
\item Factorise $x ^ { 2 } - 4 x - 12$.
\item Sketch the graph with equation $y = x ^ { 2 } - 4 x - 12$, stating the values where the curve crosses the coordinate axes.
\item \begin{enumerate}[label=(\roman*)]
\item Express $x ^ { 2 } - 4 x - 12$ in the form $( x - p ) ^ { 2 } - q$, where $p$ and $q$ are positive integers.
\item Hence find the minimum value of $x ^ { 2 } - 4 x - 12$.
\end{enumerate}\item The curve with equation $y = x ^ { 2 } - 4 x - 12$ is translated by the vector $\left[ \begin{array} { r } - 3 \\ 2 \end{array} \right]$. Find an equation of the new curve. You need not simplify your answer.
\end{enumerate}

\hfill \mbox{\textit{AQA C1 2012 Q2 [10]}}