Edexcel D1 2008 June — Question 5 11 marks

Exam BoardEdexcel
ModuleD1 (Decision Mathematics 1)
Year2008
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNetwork Flows
TypeState initial flow value
DifficultyEasy -1.2 This is a straightforward network flows question requiring basic reading of a diagram and application of standard definitions (flow conservation, saturated arcs, cut capacity). Parts (a)-(d) are direct recall/observation, (e) requires simple inspection, and (f) applies the max-flow min-cut theorem. Significantly easier than average A-level questions as it tests only basic understanding with minimal calculation.
Spec7.04f Network problems: choosing appropriate algorithm

5. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{be646775-535e-4105-86b4-ffc7eda4fa51-5_819_1421_251_322} \captionsetup{labelformat=empty} \caption{Figure 5}
\end{figure} Figure 5 shows a capacitated, directed network of pipes. The number on each arc represents the capacity of that pipe. The numbers in circles represent a feasible flow.
  1. State the values of \(x\) and \(y\).
  2. List the saturated arcs.
  3. State the value of the feasible flow.
  4. State the capacities of the cuts \(\mathrm { C } _ { 1 } , \mathrm { C } _ { 2 }\), and \(\mathrm { C } _ { 3 }\).
  5. By inspection, find a flow-augmenting route to increase the flow by one unit. You must state your route.
  6. Prove that the new flow is maximal.

AnswerMarks Guidance
(a) \(x = 9, y = 11\)B1, B1 (2 marks)
Guidance: 1B1: cao (permit B1 if 2 correct answers, but transposed). 2B1: cao
AnswerMarks Guidance
(b) AC DC DT ETB2, 1, 0 (2 marks)
Guidance: 1B1: correct (condone one error – omission or extra). 2B1: all correct (no omissions or extras)
AnswerMarks Guidance
(c) 36B1 (1 mark)
Guidance: 1B1: cao
AnswerMarks Guidance
(d) \(C_1 = 49, C_2 = 48, C_3 = 39\)B1, B1, B1 (3 marks)
Guidance: 1B1: cao. 2B1: cao. 3B1: cao
AnswerMarks Guidance
(e) e.g. SAECTB1 (1 mark)
Guidance: 1B1: A correct route (flow value of 1 given)
AnswerMarks Guidance
(f) maximum flow = minimum cut. cut through DT, DC, AC and AEM1 A1 (2 marks)
Guidance: 1M1: Must have attempted (e) and made an attempt at a cut. 1A1: cut correct – may be drawn. Refer to max flow-min cut theorem. three words out of four.
Total for Q5: 11 marks
**(a)** $x = 9, y = 11$ | B1, B1 | (2 marks) |

**Guidance:** 1B1: cao (permit B1 if 2 correct answers, but transposed). 2B1: cao

**(b)** AC DC DT ET | B2, 1, 0 | (2 marks) |

**Guidance:** 1B1: correct (condone one error – omission or extra). 2B1: all correct (no omissions or extras)

**(c)** 36 | B1 | (1 mark) |

**Guidance:** 1B1: cao

**(d)** $C_1 = 49, C_2 = 48, C_3 = 39$ | B1, B1, B1 | (3 marks) |

**Guidance:** 1B1: cao. 2B1: cao. 3B1: cao

**(e)** e.g. SAECT | B1 | (1 mark) |

**Guidance:** 1B1: A correct route (flow value of 1 given)

**(f)** maximum flow = minimum cut. cut through DT, DC, AC and AE | M1 A1 | (2 marks) |

**Guidance:** 1M1: Must have attempted (e) and made an attempt at a cut. 1A1: cut correct – may be drawn. Refer to max flow-min cut theorem. three words out of four.

**Total for Q5: 11 marks**

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5.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{be646775-535e-4105-86b4-ffc7eda4fa51-5_819_1421_251_322}
\captionsetup{labelformat=empty}
\caption{Figure 5}
\end{center}
\end{figure}

Figure 5 shows a capacitated, directed network of pipes. The number on each arc represents the capacity of that pipe. The numbers in circles represent a feasible flow.
\begin{enumerate}[label=(\alph*)]
\item State the values of $x$ and $y$.
\item List the saturated arcs.
\item State the value of the feasible flow.
\item State the capacities of the cuts $\mathrm { C } _ { 1 } , \mathrm { C } _ { 2 }$, and $\mathrm { C } _ { 3 }$.
\item By inspection, find a flow-augmenting route to increase the flow by one unit. You must state your route.
\item Prove that the new flow is maximal.
\end{enumerate}

\hfill \mbox{\textit{Edexcel D1 2008 Q5 [11]}}