CAIE P2 2019 March — Question 5 9 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2019
SessionMarch
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeRearrange to iterative form
DifficultyModerate -0.3 This is a straightforward fixed-point iteration question requiring algebraic rearrangement (substituting y=10 and taking logarithms), applying a given iterative formula with a calculator, and finding a derivative using quotient rule. All steps are routine A-level techniques with no novel problem-solving required, making it slightly easier than average.
Spec1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

5 The equation of a curve is \(y = \frac { \mathrm { e } ^ { 2 x } } { 4 x + 1 }\) and the point \(P\) on the curve has \(y\)-coordinate 10 .
  1. Show that the \(x\)-coordinate of \(P\) satisfies the equation \(x = \frac { 1 } { 2 } \ln ( 40 x + 10 )\).
  2. Use the iterative formula \(x _ { n + 1 } = \frac { 1 } { 2 } \ln \left( 40 x _ { n } + 10 \right)\) with \(x _ { 1 } = 2.3\) to find the \(x\)-coordinate of \(P\) correct to 4 significant figures. Give the result of each iteration to 6 significant figures.
  3. Find the gradient of the curve at \(P\), giving the answer correct to 3 significant figures.

Question 5(i):
AnswerMarks Guidance
AnswerMark Guidance
Attempt rearrangement of \(\dfrac{e^{2x}}{4x+1} = 10\) to \(x = ...\) involving lnM1
Confirm \(x = \frac{1}{2}\ln(40x + 10)\)A1 Answer given; necessary detail needed
Question 5(ii):
AnswerMarks Guidance
AnswerMark Guidance
Use iteration process correctly at least onceM1
Obtain final answer 2.316A1
Show sufficient iterations to 6 sf to justify answer or show a sign change in the interval \([2.3155,\ 2.3165]\)A1
Question 5(iii):
AnswerMarks Guidance
AnswerMark Guidance
Use quotient rule (or product rule) to find derivativeM1
Obtain \(\dfrac{2e^{2x}(4x+1) - 4e^{2x}}{(4x+1)^2}\) or equivalentA1
Substitute answer from part (ii) (or more accurate value) into attempt at first derivativeM1
Obtain 16.1A1
## Question 5(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| Attempt rearrangement of $\dfrac{e^{2x}}{4x+1} = 10$ to $x = ...$ involving ln | M1 | |
| Confirm $x = \frac{1}{2}\ln(40x + 10)$ | A1 | Answer given; necessary detail needed |

## Question 5(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use iteration process correctly at least once | M1 | |
| Obtain final answer 2.316 | A1 | |
| Show sufficient iterations to 6 sf to justify answer or show a sign change in the interval $[2.3155,\ 2.3165]$ | A1 | |

## Question 5(iii):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use quotient rule (or product rule) to find derivative | M1 | |
| Obtain $\dfrac{2e^{2x}(4x+1) - 4e^{2x}}{(4x+1)^2}$ or equivalent | A1 | |
| Substitute answer from part (ii) (or more accurate value) into attempt at first derivative | M1 | |
| Obtain 16.1 | A1 | |

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5 The equation of a curve is $y = \frac { \mathrm { e } ^ { 2 x } } { 4 x + 1 }$ and the point $P$ on the curve has $y$-coordinate 10 .\\
(i) Show that the $x$-coordinate of $P$ satisfies the equation $x = \frac { 1 } { 2 } \ln ( 40 x + 10 )$.\\

(ii) Use the iterative formula $x _ { n + 1 } = \frac { 1 } { 2 } \ln \left( 40 x _ { n } + 10 \right)$ with $x _ { 1 } = 2.3$ to find the $x$-coordinate of $P$ correct to 4 significant figures. Give the result of each iteration to 6 significant figures.\\

(iii) Find the gradient of the curve at $P$, giving the answer correct to 3 significant figures.\\

\hfill \mbox{\textit{CAIE P2 2019 Q5 [9]}}