| Exam Board | Edexcel |
|---|---|
| Module | S3 (Statistics 3) |
| Year | 2013 |
| Session | June |
| Marks | 14 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Chi-squared goodness of fit |
| Type | Chi-squared goodness of fit: Normal |
| Difficulty | Standard +0.3 This is a standard chi-squared goodness of fit test for normality with straightforward calculations. Part (a) requires routine mean and variance calculations from grouped data, part (b) involves basic normal distribution probability calculations, and part (c) is a textbook application of the chi-squared test. The question is slightly easier than average because the expected frequencies are mostly given, reducing computational burden, and the procedure is entirely standard with no novel problem-solving required. |
| Spec | 2.02g Calculate mean and standard deviation2.02h Recognize outliers5.06b Fit prescribed distribution: chi-squared test5.06c Fit other distributions: discrete and continuous |
| Waiting time in minutes \(( x )\) | Frequency |
| \(0 - 3\) | 8 |
| \(3 - 5\) | 12 |
| \(5 - 6\) | 13 |
| \(6 - 8\) | 9 |
| \(8 - 12\) | 8 |
| Waiting Time | \(x < 3\) | \(3 - 5\) | \(5 - 6\) | \(6 - 8\) | \(x > 8\) |
| Expected Frequency | 8.56 | 12.73 | 7.56 | \(a\) | \(b\) |
4. Customers at a post office are timed to see how long they wait until being served at the counter. A random sample of 50 customers is chosen and their waiting times, $x$ minutes, are summarised in Table 1.
\begin{table}[h]
\begin{center}
\begin{tabular}{ | c | c | }
\hline
Waiting time in minutes $( x )$ & Frequency \\
\hline
$0 - 3$ & 8 \\
\hline
$3 - 5$ & 12 \\
\hline
$5 - 6$ & 13 \\
\hline
$6 - 8$ & 9 \\
\hline
$8 - 12$ & 8 \\
\hline
\end{tabular}
\captionsetup{labelformat=empty}
\caption{Table 1}
\end{center}
\end{table}
\begin{enumerate}[label=(\alph*)]
\item Show that an estimate of $\bar { x } = 5.49$ and an estimate of $s _ { x } ^ { 2 } = 6.88$
The post office manager believes that the customers' waiting times can be modelled by a normal distribution.\\
Assuming the data is normally distributed, she calculates the expected frequencies for these data and some of these frequencies are shown in Table 2.
\begin{table}[h]
\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | }
\hline
Waiting Time & $x < 3$ & $3 - 5$ & $5 - 6$ & $6 - 8$ & $x > 8$ \\
\hline
Expected Frequency & 8.56 & 12.73 & 7.56 & $a$ & $b$ \\
\hline
\end{tabular}
\captionsetup{labelformat=empty}
\caption{Table 2}
\end{center}
\end{table}
\item Find the value of $a$ and the value of $b$.
\item Test, at the $5 \%$ level of significance, the manager's belief. State your hypotheses clearly.
\end{enumerate}
\hfill \mbox{\textit{Edexcel S3 2013 Q4 [14]}}