Edexcel S2 2013 January — Question 1 5 marks

Exam BoardEdexcel
ModuleS2 (Statistics 2)
Year2013
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicApproximating the Binomial to the Poisson distribution
TypeState conditions for Poisson approximation
DifficultyEasy -1.2 Part (a) is pure recall of standard conditions (n large, p small, np moderate). Part (b) is a routine application with given parameters requiring only P(X ≥ 4) = 1 - P(X ≤ 3) using tables or calculator. No problem-solving or insight needed, just standard bookwork and direct calculation.
Spec2.04d Normal approximation to binomial5.02n Sum of Poisson variables: is Poisson

  1. (a) Write down the conditions under which the Poisson distribution can be used as an approximation to the binomial distribution.
The probability of any one letter being delivered to the wrong house is 0.01 On a randomly selected day Peter delivers 1000 letters.
(b) Using a Poisson approximation, find the probability that Peter delivers at least 4 letters to the wrong house. Give your answer to 4 decimal places.

Question 1:
Part (a):
AnswerMarks Guidance
AnswerMark Guidance
\(n\) largeB1 Accept: \(n\) (number of trials) large/high/big, \(n > 50\), or any number larger than 50
\(p\) smallB1 Accept: \(p\) (probability) small/close to \(0\), \(p < 0.2\), or any number less than 0.2. Do not accept "low". Must appear in part (a).
(2)
Part (b):
AnswerMarks Guidance
AnswerMark Guidance
Let \(X\) be the number of letters delivered to the wrong house Definition of variable
\(X \sim B(1000, 0.01)\)
\(\text{Po}(10)\)B1 Award for writing or using \(\text{Po}(10)\)
\(P(X \geq 4) = 1 - P(X \leq 3)\)M1 Using a Poisson (\(\lambda\) need not equal 10) and writing/using \(1 - P(X \leq 3)\). Do not accept \(1 - P(X < 4)\) unless they have used \(1 - P(X \leq 3)\)
\(= 1 - 0.0103\)
\(= 0.9897\)A1 cao, must be 4 dp
(3)
Total 5
NB:
- An answer of \(\approx 0.990\) on its own gains B0M0A0 unless there is evidence that \(\text{Po}(10)\) is used, in which case it gets B1M1A0
- Using \(B(1000, 0.01)\) gives \(0.989927\ldots\) and gains B0M0A0
## Question 1:

**Part (a):**

| Answer | Mark | Guidance |
|--------|------|----------|
| $n$ large | B1 | Accept: $n$ (number of trials) large/high/big, $n > 50$, or any number larger than 50 |
| $p$ small | B1 | Accept: $p$ (probability) small/close to $0$, $p < 0.2$, or any number less than 0.2. Do **not** accept "low". Must appear in part (a). |
| | **(2)** | |

---

**Part (b):**

| Answer | Mark | Guidance |
|--------|------|----------|
| Let $X$ be the number of letters delivered to the wrong house | — | Definition of variable |
| $X \sim B(1000, 0.01)$ | — | |
| $\text{Po}(10)$ | B1 | Award for writing or using $\text{Po}(10)$ |
| $P(X \geq 4) = 1 - P(X \leq 3)$ | M1 | Using a Poisson ($\lambda$ need not equal 10) and writing/using $1 - P(X \leq 3)$. Do not accept $1 - P(X < 4)$ unless they have used $1 - P(X \leq 3)$ |
| $= 1 - 0.0103$ | — | |
| $= 0.9897$ | A1 | cao, must be 4 dp |
| | **(3)** | |
| | **Total 5** | |

**NB:**
- An answer of $\approx 0.990$ on its own gains **B0M0A0** unless there is evidence that $\text{Po}(10)$ is used, in which case it gets **B1M1A0**
- Using $B(1000, 0.01)$ gives $0.989927\ldots$ and gains **B0M0A0**
\begin{enumerate}
  \item (a) Write down the conditions under which the Poisson distribution can be used as an approximation to the binomial distribution.
\end{enumerate}

The probability of any one letter being delivered to the wrong house is 0.01 On a randomly selected day Peter delivers 1000 letters.\\
(b) Using a Poisson approximation, find the probability that Peter delivers at least 4 letters to the wrong house.

Give your answer to 4 decimal places.\\

\hfill \mbox{\textit{Edexcel S2 2013 Q1 [5]}}