Edexcel S1 2006 June — Question 4 7 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Year2006
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicUniform Distribution
TypeVariance of linear transformation
DifficultyEasy -1.2 This is a straightforward application of standard results for expectation and variance of linear transformations. Part (a) requires recall of the discrete uniform distribution formula or simple calculation; parts (b) and (c) are direct applications of E(aX+b) and Var(aX+b) rules with no problem-solving required. This is easier than average A-level content.
Spec2.04a Discrete probability distributions5.02b Expectation and variance: discrete random variables5.02e Discrete uniform distribution

  1. The random variable \(X\) has the discrete uniform distribution
$$\mathrm { P } ( X = x ) = \frac { 1 } { 5 } , \quad x = 1,2,3,4,5$$
  1. Write down the value of \(\mathrm { E } ( X )\) and show that \(\operatorname { Var } ( X ) = 2\). Find
  2. \(\mathrm { E } ( 3 X - 2 )\),
  3. \(\operatorname { Var } ( 4 - 3 X )\).

Part (a):
AnswerMarks
\(E(X) = 3\)B1
\(\text{Var}(X) = \frac{25-1}{12} = 2\)M1A1
AG
\(\text{Var}(X) = 1^2 \times \frac{1}{5} + 2^2 \times \frac{1}{5} + 3^2 \times \frac{1}{5} + \ldots - 3^2 = 11 - 9 = 2\)
AG
Accept (55/5)-9 as minimum evidence.
Part (b):
AnswerMarks
\(E(3X - 2) = 3E(X) - 2 = 7\)M1A1
Score 2 marks
Part (c):
AnswerMarks
\(\text{Var}(4 - 3x) = 3^2 \text{Var}(X) = 18\)M1A1
Score 2 marks
Total 7 marks
**Part (a):**

| $E(X) = 3$ | B1 |
| $\text{Var}(X) = \frac{25-1}{12} = 2$ | M1A1 |
| **AG** | |
| $\text{Var}(X) = 1^2 \times \frac{1}{5} + 2^2 \times \frac{1}{5} + 3^2 \times \frac{1}{5} + \ldots - 3^2 = 11 - 9 = 2$ | |
| **AG** | |
| Accept (55/5)-9 as minimum evidence. | |

**Part (b):**

| $E(3X - 2) = 3E(X) - 2 = 7$ | M1A1 |
| **Score 2 marks** | |

**Part (c):**

| $\text{Var}(4 - 3x) = 3^2 \text{Var}(X) = 18$ | M1A1 |
| **Score 2 marks** | |

**Total 7 marks**

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\begin{enumerate}
  \item The random variable $X$ has the discrete uniform distribution
\end{enumerate}

$$\mathrm { P } ( X = x ) = \frac { 1 } { 5 } , \quad x = 1,2,3,4,5$$

(a) Write down the value of $\mathrm { E } ( X )$ and show that $\operatorname { Var } ( X ) = 2$.

Find\\
(b) $\mathrm { E } ( 3 X - 2 )$,\\
(c) $\operatorname { Var } ( 4 - 3 X )$.\\

\hfill \mbox{\textit{Edexcel S1 2006 Q4 [7]}}