OCR Further Discrete Specimen — Question 4 11 marks

Exam BoardOCR
ModuleFurther Discrete (Further Discrete)
SessionSpecimen
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGroups
TypeNon-group structures
DifficultyStandard +0.8 This is a multi-part game theory question requiring understanding of play-safe strategies, stability conditions, Nash equilibrium, and strategic reasoning. While the individual concepts are A-level accessible, the question demands careful analysis across five parts including a proof element (part iii) and strategic modification (part iv), making it moderately challenging but within reach for well-prepared Further Maths students.
Spec7.08a Pay-off matrix: zero-sum games7.08c Pure strategies: play-safe strategies and stable solutions7.08d Nash equilibrium: identification and interpretation

4 The table shows the pay-off matrix for player \(A\) in a two-person zero-sum game between \(A\) and \(B\). Player \(A\) Player \(B\)
Strategy \(X\)Strategy \(Y\)Strategy \(Z\)
Strategy \(P\)45- 4
Strategy \(Q\)3- 12
Strategy \(R\)402
  1. Find the play-safe strategy for player \(A\) and the play-safe strategy for player \(B\). Use the values of the play-safe strategies to determine whether the game is stable or unstable.
  2. If player \(B\) knows that player \(A\) will use their play-safe strategy, which strategy should player \(B\) use?
  3. Suppose that the value in the cell where both players use their play-safe strategies can be changed, but all other entries are unchanged. Show that there is no way to change this value that would make the game stable.
  4. Suppose, instead, that the value in one cell can be changed, but all other entries are unchanged, so that the game becomes stable. Identify a suitable cell and write down a new pay-off value for that cell which would make the game stable.
  5. Show that the zero-sum game in the table above has a Nash equilibrium and explain what this means for the players.

Question 4:
AnswerMarks Guidance
4(i) row maxi
X Y Z
min min
P 4 5 –4 –4
Q 3 –1 2 –1
R 4 0 2 0 *
col max 4 5 2
minimax *
Play-safe for player A is strategy R
Play-safe for player B is strategy Z
AnswerMarks
Unstable, since 0(cid:122)2M1
M1
A1
AnswerMarks
[3]1.1
1.1
AnswerMarks
2.2an
e
AnswerMarks Guidance
oePlay-safe values not equal
4(ii) If player A uses strategy R, player B would get
the best pay-off by changing from Z to YB1
[1]i2.2a m
4(iii) Increasing entry in (R, Z ) has no effect on row
min and increases col max. Row maximin is
still 0 and col minimax is greater thapn 2, they
are not equal and the game is still unstable.
Decreasing entry has no effeSct on col max, as
(cid:11)Q, Z(cid:12)(cid:32)2, and may or may not decrease row
min. Row maximin is either still 0 or is less
than 0 and col minimax is still 2, they are not
AnswerMarks
equal and the game is still unstable.e
E1
E1
AnswerMarks
[2]c
2.4
AnswerMarks
2.4Describing what happens if entry is
increased
Describing what happens if entry is
decreased
AnswerMarks Guidance
4(iv) e.g. row R column Y is increased to 2 (or more)
A1
AnswerMarks
[2]2.1
2.3Identifying a suitable cell
Giving a valid new value
AnswerMarks Guidance
45 –4
40 2
4(v) Player A: (P, Y ), (Q, X ), (R, X )
Player B: (Q, X ), (R, Y ), (P, Z )
When player A chooses row Q and player B
choses column X it is a Nash equilibrium
Neither player would want to change, unless
AnswerMarks
the other changed as wellM1
A1
E1
AnswerMarks
[3]1.1
2.5
AnswerMarks
2.4Identifying cells where row maxima
occur
(Q, X ) is a Nash equilibrium
Explaining Nash equilibrium in context
Question 4:
4 | (i) | row maxi
X Y Z
min min
P 4 5 –4 –4
Q 3 –1 2 –1
R 4 0 2 0 *
col max 4 5 2
minimax *
Play-safe for player A is strategy R
Play-safe for player B is strategy Z
Unstable, since 0(cid:122)2 | M1
M1
A1
[3] | 1.1
1.1
2.2a | n
e
oe | Play-safe values not equal
4 | (ii) | If player A uses strategy R, player B would get
the best pay-off by changing from Z to Y | B1
[1] | i2.2a | m
4 | (iii) | Increasing entry in (R, Z ) has no effect on row
min and increases col max. Row maximin is
still 0 and col minimax is greater thapn 2, they
are not equal and the game is still unstable.
Decreasing entry has no effeSct on col max, as
(cid:11)Q, Z(cid:12)(cid:32)2, and may or may not decrease row
min. Row maximin is either still 0 or is less
than 0 and col minimax is still 2, they are not
equal and the game is still unstable. | e
E1
E1
[2] | c
2.4
2.4 | Describing what happens if entry is
increased
Describing what happens if entry is
decreased
4 | (iv) | e.g. row R column Y is increased to 2 (or more) | M1
A1
[2] | 2.1
2.3 | Identifying a suitable cell
Giving a valid new value
4 | 5 | –4
4 | 0 | 2
4 | (v) | Player A: (P, Y ), (Q, X ), (R, X )
Player B: (Q, X ), (R, Y ), (P, Z )
When player A chooses row Q and player B
choses column X it is a Nash equilibrium
Neither player would want to change, unless
the other changed as well | M1
A1
E1
[3] | 1.1
2.5
2.4 | Identifying cells where row maxima
occur
(Q, X ) is a Nash equilibrium
Explaining Nash equilibrium in context
4 The table shows the pay-off matrix for player $A$ in a two-person zero-sum game between $A$ and $B$.

Player $A$\\
Player $B$

\begin{center}
\begin{tabular}{ l | c | c | c }
 & Strategy $X$ & Strategy $Y$ & Strategy $Z$ \\
\hline
Strategy $P$ & 4 & 5 & - 4 \\
\hline
Strategy $Q$ & 3 & - 1 & 2 \\
\hline
Strategy $R$ & 4 & 0 & 2 \\
\hline
\end{tabular}
\end{center}

(i) Find the play-safe strategy for player $A$ and the play-safe strategy for player $B$. Use the values of the play-safe strategies to determine whether the game is stable or unstable.\\
(ii) If player $B$ knows that player $A$ will use their play-safe strategy, which strategy should player $B$ use?\\
(iii) Suppose that the value in the cell where both players use their play-safe strategies can be changed, but all other entries are unchanged. Show that there is no way to change this value that would make the game stable.\\
(iv) Suppose, instead, that the value in one cell can be changed, but all other entries are unchanged, so that the game becomes stable. Identify a suitable cell and write down a new pay-off value for that cell which would make the game stable.\\
(v) Show that the zero-sum game in the table above has a Nash equilibrium and explain what this means for the players.

\hfill \mbox{\textit{OCR Further Discrete  Q4 [11]}}