| Exam Board | OCR |
|---|---|
| Module | Further Mechanics (Further Mechanics) |
| Year | 2020 |
| Session | November |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Centre of Mass 2 |
| Type | Lamina in equilibrium with applied force |
| Difficulty | Challenging +1.2 This is a Further Maths mechanics question requiring centre of mass calculations via integration (parts a-b) and moments equilibrium with an applied force (parts c-d). While it involves multiple steps and integration of a trigonometric function, the techniques are standard for FM mechanics: finding centroids using standard formulas, then taking moments about the hinge. The 'show that' in part (a) provides scaffolding, and the equilibrium problem is straightforward once the setup is understood. More demanding than typical A-level mechanics but routine for Further Maths students. |
| Spec | 3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force6.04c Composite bodies: centre of mass6.04d Integration: for centre of mass of laminas/solids |
| Answer | Marks | Guidance |
|---|---|---|
| 5 | (a) | 5 |
| Answer | Marks |
|---|---|
| 30.716... | M1 |
| Answer | Marks |
|---|---|
| [2] | 1.1 |
| 1.1 | BC Attempt to use formula |
| Answer | Marks | Guidance |
|---|---|---|
| 5 | (b) | 5 |
| Answer | Marks |
|---|---|
| 3.11 (3 sf) | M1 |
| Answer | Marks |
|---|---|
| [2] | 1.1 |
| 1.1 | BC Attempt to use formula |
| Answer | Marks | Guidance |
|---|---|---|
| 5 | (c) | The (part of the) binding (attached to the cover) is light |
| Answer | Marks |
|---|---|
| The CoM of the badge is at A oe | B1 |
| Answer | Marks |
|---|---|
| [2] | 3.5b |
| 3.5b | eg The binding has no mass |
| Answer | Marks | Guidance |
|---|---|---|
| 5 | (d) | π π |
| Answer | Marks |
|---|---|
| P = 2.02 | M1 |
| Answer | Marks |
|---|---|
| [3] | 3.4 |
| Answer | Marks |
|---|---|
| 1.1 | Total ‘clockwise’ moment |
| Answer | Marks |
|---|---|
| moment | May use new =2.523... |
Question 5:
5 | (a) | 5
∫ x(6+sinx)dx
72.622...
x = 0 =
∫ 5 (6+sinx)dx 30.716...
0
72.622...
= =2.36 (3 sf)
30.716... | M1
A1
[2] | 1.1
1.1 | BC Attempt to use formula
and either top or bottom
correct soi
AG. Both must be seen, or
correct 2.364… seen
5 | (b) | 5
∫ 1(6+sinx)2dx
2 95.616...
y = 0 =
∫ 5 (6+sinx)dx 30.716...
0
3.11 (3 sf) | M1
A1
[2] | 1.1
1.1 | BC Attempt to use formula
and either top or bottom
correct soi
5 | (c) | The (part of the) binding (attached to the cover) is light
oe
The CoM of the badge is at A oe | B1
B1
[2] | 3.5b
3.5b | eg The binding has no mass
or the binding is very small so
that the mass is concentrated
at the hinge or the binding is
smooth
eg The badge is modelled as a
particle or the badge is
uniform
5 | (d) | π π
6×2.36cos +2×3cos
3 3
=P×5
P = 2.02 | M1
M1
A1
[3] | 3.4
3.4
1.1 | Total ‘clockwise’ moment
about binding axis (allow
inclusion of g if consistent)...
...equals ‘anticlockwise’
moment | May use new =2.523...
𝑥𝑥̅
𝜋𝜋
8=5coPs ×𝑥𝑥̅
3
5 The cover of a children's book is modelled as being a uniform lamina $L . L$ occupies the region bounded by the $x$-axis, the curve $\mathrm { y } = 6 + \sin \mathrm { x }$ and the lines $x = 0$ and $x = 5$ (see Fig. 5.1). The centre of mass of $L$ is at the point ( $\mathrm { x } , \mathrm { y }$ ).
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{831ba5da-df19-43bb-b163-02bbddb4e2b8-4_659_540_397_244}
\captionsetup{labelformat=empty}
\caption{Fig. 5.1}
\end{center}
\end{figure}
\begin{enumerate}[label=(\alph*)]
\item Show that $\bar { X } = 2.36$, correct to 3 significant figures.
\item Find $\bar { y }$, giving your answer correct to 3 significant figures.
The cover of the book weighs 6 N . $A$ is the point on the cover with coordinates $( 3 , \bar { y } )$ and $B$ is the point on the cover with coordinates $( 5 , \bar { y } )$. A small badge of weight 2 N is attached to the cover at $A$.
The side of $L$ along the $y$-axis is attached to the rest of the book and the book is placed on a rough horizontal plane. The attachment of the cover to the book is modelled as a hinge.
The cover is held in equilibrium at an angle of $\frac { 1 } { 3 } \pi$ radians to the horizontal by a force of magnitude $P N$ acting at $B$ perpendicular to the cover (see Fig. 5.2).
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{831ba5da-df19-43bb-b163-02bbddb4e2b8-4_444_899_1889_246}
\captionsetup{labelformat=empty}
\caption{Fig. 5.2}
\end{center}
\end{figure}
\item State two additional modelling assumptions, one about the attachment of the cover and one about the badge, which are necessary to allow the value of $P$ to be determined.
\item Using the modelling assumptions, determine the value of $P$ giving your answer correct to 3 significant figures.
\end{enumerate}
\hfill \mbox{\textit{OCR Further Mechanics 2020 Q5 [9]}}