| Exam Board | OCR |
|---|---|
| Module | Further Statistics (Further Statistics) |
| Year | 2024 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Wilcoxon tests |
| Type | Critical region or test statistic properties |
| Difficulty | Challenging +1.8 This question requires understanding the connection between combinatorics and the Wilcoxon distribution (non-trivial insight), careful work with cumulative frequencies to find critical values, and algebraic manipulation to verify consistency of mean/variance formulas. While the individual components are accessible, the conceptual link in part (b) and the verification in part (c) require more sophisticated statistical reasoning than typical A-level questions. |
| Spec | 5.01a Permutations and combinations: evaluate probabilities5.07b Sign test: and Wilcoxon signed-rank |
| S | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 |
| Frequency | 1 | 1 | 2 | 3 | 5 | 7 | 10 | 13 | 17 |
| Cumulative Frequency | 1 | 2 | 4 | 7 | 12 | 19 | 29 | 42 | 59 |
| Answer | Marks | Guidance |
|---|---|---|
| 4 | (a) | 792 |
| [1] | 1.1 | Allow 12C |
| Answer | Marks |
|---|---|
| (b) | 0.02×792 (= 15.84) or |
| Answer | Marks |
|---|---|
| (15 S) 19 | M1 |
| Answer | Marks |
|---|---|
| [2] | 3.4 |
| 2.2a | Find 2% of their (a), or any one CF (> 1) their (a). (Not 59) |
| Answer | Marks |
|---|---|
| (c) | 12 n ( m + n + 1 ) = 2 0 0 , 11 m n ( m + n + 1 ) = 6 1 6 23 |
| Answer | Marks |
|---|---|
| n not an integer, hence impossible | B1 |
| Answer | Marks |
|---|---|
| [3] | 2.1 |
| Answer | Marks |
|---|---|
| 2.4 | Both correct, stated or used. |
| Answer | Marks | Guidance |
|---|---|---|
| Question | Answer | Marks |
Question 4:
4 | (a) | 792 | B1
[1] | 1.1 | Allow 12C
5
(b) | 0.02×792 (= 15.84) or
12/792 = 0.01551…, 19/792 = 0.0239…
0.0155 < 0.02 < 0.0239 so critical region is
(15 S) 19 | M1
A1
[2] | 3.4
2.2a | Find 2% of their (a), or any one CF (> 1) their (a). (Not 59)
(18 or 20 are in tables and do not imply M1 unless clear evidence)
Correct inequality from at least one correct relevant calculation.
Allow “S 19”, or just “ 19”. Not “CV = 19”.
SC: 19 with no working involving their 792: M0.
(c) | 12 n ( m + n + 1 ) = 2 0 0 , 11 m n ( m + n + 1 ) = 6 1 6 23
2
Divide: 16 n = 31 72 n = 18.5 (m = 12.5)
n not an integer, hence impossible | B1
B1*
depB1
[3] | 2.1
3.1a
2.4 | Both correct, stated or used.
Solve to get one correct answer, e.g. 7400/400, needs both
previous equations but allow if one constant wrong
Valid reason for impossible, allow “can’t be a decimal” etc, needs
both previous B1s, cwo
Question | Answer | Marks | AO | Guidance
4
\begin{enumerate}[label=(\alph*)]
\item Write down the number of ways of choosing 5 objects from 12 distinct objects.
\item Each possible set of 5 different integers selected from the integers $1,2 , \ldots , 12$ is obtained, and for each set, the sum of the 5 integers is found. The sum $S$ can take values between 15 and 50 inclusive. Part of the frequency distribution of $S$ is shown in the following table, together with the cumulative frequencies.
\begin{center}
\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|}
\hline
S & 15 & 16 & 17 & 18 & 19 & 20 & 21 & 22 & 23 \\
\hline
Frequency & 1 & 1 & 2 & 3 & 5 & 7 & 10 & 13 & 17 \\
\hline
Cumulative Frequency & 1 & 2 & 4 & 7 & 12 & 19 & 29 & 42 & 59 \\
\hline
\end{tabular}
\end{center}
Use these numbers to determine the critical region for a 1-tail Wilcoxon rank-sum test at the $2 \%$ significance level when $m = 5$ and $n = 7$.
\item A student says that, for a Wilcoxon rank-sum test on samples of size $m$ and $n$, where $m$ and $n$ are large, the mean and variance of the test statistic $R _ { m }$ are 200 and $616 \frac { 2 } { 3 }$ respectively.
Show that at least one of these values must be incorrect.
\end{enumerate}
\hfill \mbox{\textit{OCR Further Statistics 2024 Q4 [6]}}