OCR Further Statistics 2022 June — Question 2 11 marks

Exam BoardOCR
ModuleFurther Statistics (Further Statistics)
Year2022
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBivariate data
TypeDistinguish dependent and independent variables
DifficultyModerate -0.8 This is a straightforward bivariate data question testing basic concepts: identifying independent/dependent variables, calculating PMCC from summary statistics using a standard formula, conducting a routine hypothesis test, and recognizing correlation is invariant under linear transformations. All parts are standard textbook exercises requiring recall and direct application of formulas with no problem-solving or novel insight needed.
Spec5.08a Pearson correlation: calculate pmcc5.08d Hypothesis test: Pearson correlation

2 The directors of a large company believe that there are more computer failures in the Head Office when temperatures are higher. They obtain data for the Head Office for the maximum temperature, \(T ^ { \circ } \mathrm { C }\), and the number of computer failures, \(X\), on each of 12 randomly chosen days.
  1. State which of the following words can be applied to \(T\). Dependent Independent Controlled Response The data is summarised as follows. \(n = 12 \quad \sum t = 261 \quad \sum x = 41 \quad \sum t ^ { 2 } = 5869 \quad \sum x ^ { 2 } = 311 \quad \sum \mathrm { tx } = 1021\)
  2. Calculate the value of the product moment correlation coefficient \(r\).
  3. The directors wish to investigate their belief using a significance test at the \(1 \%\) level.
    1. Explain why a 1-tail test is appropriate in this situation.
    2. Carry out the test.
  4. One of the directors prefers the temperatures to be given in Fahrenheit ( \({ } ^ { \circ } \mathrm { F }\) ), rather than Centigrade ( \({ } ^ { \circ } \mathrm { C }\) ). The relationship between F and C is \(\mathrm { F } = \frac { 9 } { 5 } \mathrm { C } + 32\).
    State the value of \(r\) that would result from using temperatures in Fahrenheit in the calculation.

Question 2:
AnswerMarks Guidance
2(a) Independent (and no others)
(b)0.713 BC B2
[2]1.1
1.1SC: If B0, give B1 for any 2 of 16.02, 14.24,
10.77, or any 2 of 192.25, 170.9, 129.25 seene.g. 769/4, 2051/12, 517/4
(c)(i) “More computer failures when
temperatures are higher”, rather than
“number of failures is related to higher or
AnswerMarks Guidance
lower temperatures”B1
[1]2.4 Oe
Allow “Looking for positive correlation”, etc
AnswerMarks Guidance
(c)(ii) H  = 0, H :  > 0
0: 1
where  is the population PMCC between
temperature and number of failures
CV = 0.6581
0.713 > 0.6581
Reject H . Significant evidence of
0
(positive) correlation between temperature
AnswerMarks
and number of failuresB2
B1
B1ft
M1ft
A1ft
AnswerMarks
[6]1.1
2.5
1.1
1.1
1.1
AnswerMarks
2.2bTreat association and correlation as equivalent
One error, e.g. 2-tail, or  not defined: B1
(allow H :   0). Allow omission of “population”
0
(or “true”) or of context, but not of both
Correct CV, or p = 0.00462
Explicit comparison, their r, allow “pmcc > CV”
FT on their r, needs 0.6581, 0.6851, 0.7079,
AnswerMarks
0.4973 or 0.5760; contextualised, not too definiteSee Appendix for exemplars
Verbal, e.g. H : no correlation between
0
temperature and number of failures, H :
1
positive correlation: max B1, one error B0
Their CV must be from tables for r or r
s
If inconsistent with comparison, M0A0
Not “insufficient evidence of no correlation
between …”
AnswerMarks Guidance
(d)0.713 B1ft
[1]1.2 Their (b). Allow “unchanged”, etc.
Question 2:
2 | (a) | Independent (and no others) | B1 | 2.5 | Fully correct only
(b) | 0.713 BC | B2
[2] | 1.1
1.1 | SC: If B0, give B1 for any 2 of 16.02, 14.24,
10.77, or any 2 of 192.25, 170.9, 129.25 seen | e.g. 769/4, 2051/12, 517/4
(c) | (i) | “More computer failures when
temperatures are higher”, rather than
“number of failures is related to higher or
lower temperatures” | B1
[1] | 2.4 | Oe
Allow “Looking for positive correlation”, etc
(c) | (ii) | H  = 0, H :  > 0
0: 1
where  is the population PMCC between
temperature and number of failures
CV = 0.6581
0.713 > 0.6581
Reject H . Significant evidence of
0
(positive) correlation between temperature
and number of failures | B2
B1
B1ft
M1ft
A1ft
[6] | 1.1
2.5
1.1
1.1
1.1
2.2b | Treat association and correlation as equivalent
One error, e.g. 2-tail, or  not defined: B1
(allow H :   0). Allow omission of “population”
0
(or “true”) or of context, but not of both
Correct CV, or p = 0.00462
Explicit comparison, their r, allow “pmcc > CV”
FT on their r, needs 0.6581, 0.6851, 0.7079,
0.4973 or 0.5760; contextualised, not too definite | See Appendix for exemplars
Verbal, e.g. H : no correlation between
0
temperature and number of failures, H :
1
positive correlation: max B1, one error B0
Their CV must be from tables for r or r
s
If inconsistent with comparison, M0A0
Not “insufficient evidence of no correlation
between …”
(d) | 0.713 | B1ft
[1] | 1.2 | Their (b). Allow “unchanged”, etc.
2 The directors of a large company believe that there are more computer failures in the Head Office when temperatures are higher. They obtain data for the Head Office for the maximum temperature, $T ^ { \circ } \mathrm { C }$, and the number of computer failures, $X$, on each of 12 randomly chosen days.
\begin{enumerate}[label=(\alph*)]
\item State which of the following words can be applied to $T$.

Dependent Independent Controlled Response

The data is summarised as follows.\\
$n = 12 \quad \sum t = 261 \quad \sum x = 41 \quad \sum t ^ { 2 } = 5869 \quad \sum x ^ { 2 } = 311 \quad \sum \mathrm { tx } = 1021$
\item Calculate the value of the product moment correlation coefficient $r$.
\item The directors wish to investigate their belief using a significance test at the $1 \%$ level.
\begin{enumerate}[label=(\roman*)]
\item Explain why a 1-tail test is appropriate in this situation.
\item Carry out the test.
\end{enumerate}\item One of the directors prefers the temperatures to be given in Fahrenheit ( ${ } ^ { \circ } \mathrm { F }$ ), rather than Centigrade ( ${ } ^ { \circ } \mathrm { C }$ ). The relationship between F and C is $\mathrm { F } = \frac { 9 } { 5 } \mathrm { C } + 32$.\\
State the value of $r$ that would result from using temperatures in Fahrenheit in the calculation.
\end{enumerate}

\hfill \mbox{\textit{OCR Further Statistics 2022 Q2 [11]}}