A plane \(\Pi\) has the equation \(\mathbf { r } \cdot \left( \begin{array} { r } 3 6 - 2 \end{array} \right) = 15 . C\) is the point \(( 4 , - 5,1 )\).
Find the shortest distance between \(\Pi\) and \(C\).
Lines \(l _ { 1 }\) and \(l _ { 2 }\) have the following equations.
$$\begin{aligned}
& l _ { 1 } : \mathbf { r } = \left( \begin{array} { l }
4