OCR Further Additional Pure AS 2020 November — Question 3 6 marks

Exam BoardOCR
ModuleFurther Additional Pure AS (Further Additional Pure AS)
Year2020
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumber Theory
TypeDivisibility tests and proofs
DifficultyModerate -0.5 This question tests standard divisibility rules and basic logical deduction. Part (a) requires recognizing that 26 and 13 share factors or using the alternating sum divisibility test for 13. Part (b) applies routine divisibility tests for 4 and 9. Part (c) is straightforward deduction using the given factorization. While it requires knowing specific divisibility tests, the question is largely procedural with no novel problem-solving required, making it slightly easier than average.
Spec8.02b Divisibility tests: standard tests for 2, 3, 4, 5, 8, 9, 11

3 In this question, \(N\) is the number 26132652.
  1. Without dividing \(N\) by 13, explain why 13 is a factor of \(N\).
  2. Use standard divisibility tests to show that 36 is a factor of \(N\). It is given that \(N = 36 \times 725907\).
  3. Use the results of parts (a) and (b) to deduce that 13 is a factor of 725907.

Question 3:
AnswerMarks Guidance
3(a) 13 divides each pair of digits of N (26, 13, 26, 52)
[1]2.4 Or applying a standard divisibility test
(b)4 52 (the final two digits of N) ⇒ 4
9digit-sum of N (= 27) ⇒ 9 N
Since hcf(4, 9) = 1, 4 × 9 = 36N B1
B1
B1
AnswerMarks
[3]1.1
1.1
AnswerMarks
2.4Applying these two divisibility tests
Must explain that 4, 9 are co-prime as well as state the
conclusion
AnswerMarks Guidance
(c)By Euclid’s Lemma,
1336 × 725907 and hcf(13, 36) = 1
⇒ 13725907 M1
A1
AnswerMarks
[2]2.4
2.2aM for stating “Euclid’s Lemma” (or full description of its result)
Clear outline of necessary conditions
Question 3:
3 | (a) | 13 divides each pair of digits of N (26, 13, 26, 52) | B1
[1] | 2.4 | Or applying a standard divisibility test
(b) | 4 | 52 (the final two digits of N) ⇒ 4 | N
9 | digit-sum of N (= 27) ⇒ 9 | N
Since hcf(4, 9) = 1, 4 × 9 = 36 | N | B1
B1
B1
[3] | 1.1
1.1
2.4 | Applying these two divisibility tests
Must explain that 4, 9 are co-prime as well as state the
conclusion
(c) | By Euclid’s Lemma,
13 | 36 × 725907 and hcf(13, 36) = 1
⇒ 13 | 725907 | M1
A1
[2] | 2.4
2.2a | M for stating “Euclid’s Lemma” (or full description of its result)
Clear outline of necessary conditions
3 In this question, $N$ is the number 26132652.
\begin{enumerate}[label=(\alph*)]
\item Without dividing $N$ by 13, explain why 13 is a factor of $N$.
\item Use standard divisibility tests to show that 36 is a factor of $N$.

It is given that $N = 36 \times 725907$.
\item Use the results of parts (a) and (b) to deduce that 13 is a factor of 725907.
\end{enumerate}

\hfill \mbox{\textit{OCR Further Additional Pure AS 2020 Q3 [6]}}