| Exam Board | OCR MEI |
|---|---|
| Module | AS Paper 2 (AS Paper 2) |
| Year | 2020 |
| Session | November |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Measures of Location and Spread |
| Type | Describing sampling methods |
| Difficulty | Easy -1.8 This is a straightforward AS-level statistics question testing basic recall of sampling terminology, simple descriptive statistics using a calculator, and elementary proportional calculation. All parts require minimal problem-solving—just applying standard definitions and procedures with no conceptual challenges or multi-step reasoning. |
| Spec | 2.01c Sampling techniques: simple random, opportunity, etc2.02a Interpret single variable data: tables and diagrams2.02f Measures of average and spread2.02g Calculate mean and standard deviation |
| Number of portions of fruit | 0 | 1 | 2 | 3 | 4 | 5 |
| Number of adults | 18 | 34 | 26 | 11 | 7 | 4 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Quota sampling | B1 (1.2) | |
| [1] |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Non-random | B1 (2.4) | Or equivalent. Accept 'the procedure is biased', but not 'those chosen might be biased' or 'tedious'. Ignore extra parts of explanation. |
| [1] |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| Positive skew | B1 (1.2) | |
| [1] |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| mean is 1.67 | B1 (1.1) | CAO |
| sd is 1.31 | B1 (1.1) | CAO Do not allow 1.30 or 1.3 |
| [2] |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| 20 | B1 (1.1) | NB \(44 \times \frac{100}{220}\) |
| [1] |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| (means very similar so) average number of portions of fruit consumed per child is similar to average number of portions of fruits consumed per adult | B1 (2.2a) | Condone mean for children is (slightly) less than for adults BUT must be in context of portions of fruit. ft from (d); answers must be consistent with their answers to (d) and must both be in context |
| (sd for children is lower so) less variability in number of portions of fruit consumed per day by children | B1 (2.5) | |
| [2] |
## Question 3(a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Quota sampling | B1 (1.2) | |
| **[1]** | | |
---
## Question 3(b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Non-random | B1 (2.4) | Or equivalent. Accept 'the procedure is biased', but not 'those chosen might be biased' or 'tedious'. Ignore extra parts of explanation. |
| **[1]** | | |
---
## Question 3(c):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Positive skew | B1 (1.2) | |
| **[1]** | | |
---
## Question 3(d):
| Answer | Marks | Guidance |
|--------|-------|----------|
| mean is 1.67 | B1 (1.1) | CAO |
| sd is 1.31 | B1 (1.1) | CAO Do not allow 1.30 or 1.3 |
| **[2]** | | |
---
## Question 3(e):
| Answer | Marks | Guidance |
|--------|-------|----------|
| 20 | B1 (1.1) | NB $44 \times \frac{100}{220}$ |
| **[1]** | | |
---
## Question 3(f):
| Answer | Marks | Guidance |
|--------|-------|----------|
| (means very similar so) average number of portions of fruit consumed per child is similar to average number of portions of fruits consumed per adult | B1 (2.2a) | Condone mean for children is (slightly) less than for adults BUT must be in context of portions of fruit. ft from (d); answers must be consistent with their answers to (d) and must both be in context |
| (sd for children is lower so) less variability in number of portions of fruit consumed per day by children | B1 (2.5) | |
| **[2]** | | |
---
3 A researcher is conducting an investigation into the number of portions of fruit adults consume each day. The researcher decides to ask 50 men and 50 women to complete a simple questionnaire.
\begin{enumerate}[label=(\alph*)]
\item State the type of sampling procedure the researcher is using.
\item Write down one disadvantage of this sampling procedure.
The researcher represents the data in Fig. 3.1.
\begin{figure}[h]
\begin{center}
\captionsetup{labelformat=empty}
\caption{Number of portions of fruit consumed by adults}
\includegraphics[alt={},max width=\textwidth]{c08a2212-3104-425e-8aee-7f2d46f23924-06_531_991_701_248}
\end{center}
\end{figure}
Fig. 3.1
\item Describe the shape of the distribution.
The data are summarised in the frequency table in Fig. 3.2.
\begin{table}[h]
\begin{center}
\begin{tabular}{ | l | c | c | c | c | c | c | }
\hline
Number of portions of fruit & 0 & 1 & 2 & 3 & 4 & 5 \\
\hline
Number of adults & 18 & 34 & 26 & 11 & 7 & 4 \\
\hline
\end{tabular}
\captionsetup{labelformat=empty}
\caption{Fig. 3.2}
\end{center}
\end{table}
\item For the data in Fig. 3.2, use your calculator to find
\begin{itemize}
\item the mean,
\item the standard deviation.
\end{itemize}
Give your answers correct to 2 decimal places.
A second researcher chooses a proportional stratified sample of 100 children from years 5 and 6 in a certain primary school. There are 220 children to choose from. In year 5 there are 125 children, of whom 81 are boys.
\item How many year 5 girls should be included in the sample?
The second researcher found that the mean number of portions of fruit consumed per day by the children in this sample was 1.61 and the standard deviation was 0.53 .
\item Comment on the amount of fruit consumed per day by the children compared to the amount of fruit consumed per day by the adults.
\end{enumerate}
\hfill \mbox{\textit{OCR MEI AS Paper 2 2020 Q3 [8]}}