## Question 2(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\frac{10}{4}$ | M1 | 3.4 - Any complete suvat method to find $a$, e.g. use $s = 20$ and $20 = \frac{1}{2}a \times 4^2$. Ignore units at this stage |
| $2.5, \frac{5}{2}, \frac{10}{4}$ m s$^{-2}$ (units needed) | A1 | 1.1b - Any equivalent number **with** correct units. Accept m/s$^2$, m/s/s, m per s per s |

**(2 marks)**

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## Question 2(b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Find the area with correct structure from $t=0$ to $18$: $\frac{1}{2}\times4\times10+(14\times10)$ (triangle + rectangle) **or** $\frac{1}{2}\times10\times(14+18)$ (trapezium) **or** $(18\times10)-\frac{1}{2}\times4\times10$ (rectangle − triangle) | M1 | 3.1b - Complete method using area or suvat on one or more sections to find **total** area. M0 if single suvat used for whole motion. M0 if $\frac{1}{2}$ not seen in area method |
| Correct unsimplified expression (N.B. $\frac{1}{2}\times4\times10$ may be replaced by $\frac{1}{2}\times2.5\times4^2$ using $s=ut+\frac{1}{2}at^2$, or by $\frac{10^2-0^2}{2\times2.5}$ using $v^2=u^2+2as$) | A1 | 1.1b - Correct unsimplified expression |
| $160$ (m) | A1 | 1.1b - cao. Ignore units. Correct answer **with no working** can score all 3 marks |

**(3 marks)**

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## Question 2(c):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Using area from $t=18$ to $t=24$, $= (200 - \text{their (b)})$ with correct structure **OR** $s=(200-\text{their (b)})$ using suvat to find $s$ | M1 | 3.1b - Complete method using area or suvat to give equation in $U$ only. M0 if $\frac{1}{2}$ not seen in area method. M0 if $10$ used instead of $(10-U)$ or $(10-U)$ used instead of $(10+U)$ in any equation. N.B. If their (b) is incorrect and they don't use it, allow a correct restart |
| $6U+\frac{1}{2}\times6\times(10-U)=200-\text{their (b)}$ (rectangle + triangle) **or** $\frac{1}{2}\times6\times(10+U)=200-\text{their (b)}$ (trapezium) **or** $(6\times10)-\frac{1}{2}\times6\times(10-U)=200-\text{their (b)}$ (rectangle − triangle) **or** $(10\times6)+\frac{1}{2}\left(-\frac{(10-U)}{6}\right)\times6^2=200-\text{their (b)}$ using $s=ut+\frac{1}{2}at^2$ **or** $(U\times6)-\frac{1}{2}\left(-\frac{(10-U)}{6}\right)\times6^2=200-\text{their (b)}$ using $s=vt-\frac{1}{2}at^2$ | A1ft | 1.1b - Correct unsimplified equation in $U$ only (allow $V$ or $v$ instead of $U$), **ft on their 160** |
| $\frac{10}{3} = 3\frac{1}{3}$ oe | A1 | 1.1b - Accept 3.3 or better. Ignore units. Allow use of $V$ throughout instead of $U$ including in answer. Correct answer **with no working** can score all 3 marks |

**(3 marks)**

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