2.
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{414946db-64d7-44b8-801d-2c7805ee9cc6-04_282_627_246_721}
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\caption{Figure 1}
\end{figure}
A rough plane is inclined to the horizontal at an angle \(\alpha\), where \(\tan \alpha = \frac { 3 } { 4 }\)
A small block \(B\) of mass 5 kg is held in equilibrium on the plane by a horizontal force of magnitude \(X\) newtons, as shown in Figure 1.
The force acts in a vertical plane which contains a line of greatest slope of the inclined plane.
The block \(B\) is modelled as a particle.
The magnitude of the normal reaction of the plane on \(B\) is 68.6 N .
Using the model,
- find the magnitude of the frictional force acting on \(B\),
- state the direction of the frictional force acting on \(B\).
The horizontal force of magnitude \(X\) newtons is now removed and \(B\) moves down the plane.
Given that the coefficient of friction between \(B\) and the plane is 0.5
- find the acceleration of \(B\) down the plane.