Edexcel Paper 1 2018 June — Question 4 4 marks

Exam BoardEdexcel
ModulePaper 1 (Paper 1)
Year2018
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeCompare iteration convergence
DifficultyStandard +0.3 This question requires showing α lies in an interval by substitution (routine), then using a cobweb diagram to determine convergence of an iteration. While it involves understanding fixed point iteration graphically, the reasoning is straightforward: checking if the iteration converges or diverges from the diagram. This is a standard Further Maths topic tested in a predictable way with minimal problem-solving required.
Spec1.06d Natural logarithm: ln(x) function and properties1.09a Sign change methods: locate roots1.09b Sign change methods: understand failure cases1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

  1. The curve with equation \(y = 2 \ln ( 8 - x )\) meets the line \(y = x\) at a single point, \(x = \alpha\).
    1. Show that \(3 < \alpha < 4\)
    \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{b5f50f17-9f1b-4b4c-baf3-e50de5f2ea9c-08_666_1061_445_502} \captionsetup{labelformat=empty} \caption{Figure 2}
    \end{figure} Figure 2 shows the graph of \(y = 2 \ln ( 8 - x )\) and the graph of \(y = x\).
    A student uses the iteration formula $$x _ { n + 1 } = 2 \ln \left( 8 - x _ { n } \right) , \quad n \in \mathbb { N }$$ in an attempt to find an approximation for \(\alpha\).
    Using the graph and starting with \(x _ { 1 } = 4\)
  2. determine whether or not this iteration formula can be used to find an approximation for \(\alpha\), justifying your answer.

Question 4(a):
AnswerMarks Guidance
Working/AnswerMark Guidance
Attempts \(f(3) =\) and \(f(4) =\) where \(f(x) = \pm(2\ln(8-x)-x)\)M1 2.1
\(f(3) = (2\ln 5 - 3) = (+)0.22\) and \(f(4) = (2\ln 4 - 4) = -1.23\); change of sign and function continuous in \([3,4] \Rightarrow\) RootA1* 2.4
Notes: M1 for attempting \(f(3)\) and \(f(4)\) — not routine, cannot be scored by substituting 3 and 4 in both functions separately. A1: Both values correct to at least 1 sf, correct explanation and conclusion. Allow reasons \(2\ln 8 = 3.21 > 3\), \(2\ln 4 = 2.77 < 4\) or similar.
Question 4(b):
AnswerMarks Guidance
Working/AnswerMark Guidance
Annotating graph with cobweb diagram starting at \(x_1 = 4\), at least two spiralsM1 2.4
Deduces iteration formula can be used to find approximation for \(\alpha\) because the cobweb spirals inwardsA1 2.2a
Notes: M1 for 5 or more correct straight lines in cobweb diagram. If no graph then M0 A0. A1 requires correct attempt starting at 4, deducing it can be used as iterations converge to root. Suitable reasons: "spirals inwards", "gets closer to the root", "it converges".
# Question 4(a):

| Working/Answer | Mark | Guidance |
|---|---|---|
| Attempts $f(3) =$ and $f(4) =$ where $f(x) = \pm(2\ln(8-x)-x)$ | M1 | 2.1 |
| $f(3) = (2\ln 5 - 3) = (+)0.22$ and $f(4) = (2\ln 4 - 4) = -1.23$; change of sign and function continuous in $[3,4] \Rightarrow$ Root | A1* | 2.4 |

**Notes:** M1 for attempting $f(3)$ and $f(4)$ — not routine, cannot be scored by substituting 3 and 4 in both functions separately. A1: Both values correct to at least 1 sf, correct explanation and conclusion. Allow reasons $2\ln 8 = 3.21 > 3$, $2\ln 4 = 2.77 < 4$ or similar.

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# Question 4(b):

| Working/Answer | Mark | Guidance |
|---|---|---|
| Annotating graph with cobweb diagram starting at $x_1 = 4$, at least two spirals | M1 | 2.4 |
| Deduces iteration formula **can be used** to find approximation for $\alpha$ because **the cobweb spirals inwards** | A1 | 2.2a |

**Notes:** M1 for 5 or more correct straight lines in cobweb diagram. If no graph then M0 A0. A1 requires correct attempt starting at 4, deducing it **can be used** as iterations converge to root. Suitable reasons: "spirals inwards", "gets closer to the root", "it converges".

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\begin{enumerate}
  \item The curve with equation $y = 2 \ln ( 8 - x )$ meets the line $y = x$ at a single point, $x = \alpha$.\\
(a) Show that $3 < \alpha < 4$
\end{enumerate}

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{b5f50f17-9f1b-4b4c-baf3-e50de5f2ea9c-08_666_1061_445_502}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{center}
\end{figure}

Figure 2 shows the graph of $y = 2 \ln ( 8 - x )$ and the graph of $y = x$.\\
A student uses the iteration formula

$$x _ { n + 1 } = 2 \ln \left( 8 - x _ { n } \right) , \quad n \in \mathbb { N }$$

in an attempt to find an approximation for $\alpha$.\\
Using the graph and starting with $x _ { 1 } = 4$\\
(b) determine whether or not this iteration formula can be used to find an approximation for $\alpha$, justifying your answer.

\hfill \mbox{\textit{Edexcel Paper 1 2018 Q4 [4]}}