Edexcel AS Paper 1 2018 June — Question 10 4 marks

Exam BoardEdexcel
ModuleAS Paper 1 (AS Paper 1)
Year2018
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiation from First Principles
TypeFirst principles: x³ terms
DifficultyModerate -0.5 This is a standard first principles differentiation question for a single power term (x³). While it requires knowledge of the binomial expansion and algebraic manipulation, it's a routine textbook exercise that follows a well-established method. It's slightly easier than average because it's a direct application of a standard technique with no problem-solving required, though not trivial since students must execute the proof correctly.
Spec1.07g Differentiation from first principles: for small positive integer powers of x

  1. Prove, from first principles, that the derivative of \(x ^ { 3 }\) is \(3 x ^ { 2 }\)

Question 10:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Considers \(\frac{(x+h)^3 - x^3}{h}\)B1 2.1 — Correct fraction for gradient of chord. May also be awarded for expanded form. Does not have to be linked to gradient of chord
Expands \((x+h)^3 = x^3 + 3x^2h + 3xh^2 + h^3\)M1 1.1b — Look for two correct terms, most likely \(x^3 + ... + h^3\). Independent of B1
Gradient of chord \(= \frac{3x^2h + 3xh^2 + h^3}{h} = 3x^2 + 3xh + h^2\)A1 1.1b — Exact unsimplified equivalent such as \(3x^2 + 2xh + xh + h^2\) also acceptable
As \(h \to 0\), \(3x^2 + 3xh + h^2 \to 3x^2\) so derivative \(= 3x^2\)A1* 2.5 — CSO. Must link gradient of chord to gradient of curve. Do not allow \(h=0\) alone without limit being considered. Condone invisible brackets for expansion of \((x+h)^3\) as long as only seen as intermediate working
## Question 10:

| Answer/Working | Mark | Guidance |
|---|---|---|
| Considers $\frac{(x+h)^3 - x^3}{h}$ | B1 | 2.1 — Correct fraction for gradient of chord. May also be awarded for expanded form. Does not have to be linked to gradient of chord |
| Expands $(x+h)^3 = x^3 + 3x^2h + 3xh^2 + h^3$ | M1 | 1.1b — Look for two correct terms, most likely $x^3 + ... + h^3$. Independent of B1 |
| Gradient of chord $= \frac{3x^2h + 3xh^2 + h^3}{h} = 3x^2 + 3xh + h^2$ | A1 | 1.1b — Exact unsimplified equivalent such as $3x^2 + 2xh + xh + h^2$ also acceptable |
| As $h \to 0$, $3x^2 + 3xh + h^2 \to 3x^2$ so derivative $= 3x^2$ | A1* | 2.5 — CSO. Must link gradient of chord to gradient of curve. Do not allow $h=0$ alone without limit being considered. Condone invisible brackets for expansion of $(x+h)^3$ as long as only seen as intermediate working |
\begin{enumerate}
  \item Prove, from first principles, that the derivative of $x ^ { 3 }$ is $3 x ^ { 2 }$
\end{enumerate}

\hfill \mbox{\textit{Edexcel AS Paper 1 2018 Q10 [4]}}