CAIE P3 2015 November — Question 7 10 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2015
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration with Partial Fractions
TypeFactorization then partial fractions
DifficultyStandard +0.3 This is a standard A-level integration question combining polynomial factorization and partial fractions. Part (i) is routine factor verification using substitution or division. Part (ii) requires factorizing the cubic (given one factor), decomposing into partial fractions, and integrating—all well-practiced techniques in P3/C4. The numerator degree is less than denominator, avoiding the need for polynomial division. Slightly above average difficulty due to the multi-step nature and cubic factorization, but follows a predictable template without requiring novel insight.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02y Partial fractions: decompose rational functions1.08j Integration using partial fractions

7
  1. Show that ( \(x + 1\) ) is a factor of \(4 x ^ { 3 } - x ^ { 2 } - 11 x - 6\).
  2. Find \(\int \frac { 4 x ^ { 2 } + 9 x - 1 } { 4 x ^ { 3 } - x ^ { 2 } - 11 x - 6 } \mathrm {~d} x\).

(i)
Either
AnswerMarks
Substitute \(x = -1\) and evaluateM1
Obtain 0 and conclude \(x + 1\) is a factorA1
Or
AnswerMarks Guidance
Divide by \(x + 1\) and obtain a constant remainderM1
Obtain remainder = 0 and conclude \(x + 1\) is a factorA1 [2]
(ii)
AnswerMarks Guidance
Attempt division, or equivalent, at least as far as quotient \(4x^2 + kx\)M1
Obtain complete quotient \(4x^2 - 5x - 6\)A1
State form \(\frac{A}{x + 1} + \frac{B}{x - 2} + \frac{C}{4x + 3}\)A1
Use relevant method for finding at least one constantM1
Obtain one of \(A = -2, B = 1, C = 8\)A1
Obtain all three valuesA1
Integrate to obtain three terms each involving natural logarithm of linear formM1
Obtain \(-2\ln(x + 1) + \ln(x - 2) + 2\ln(4x + 3)\), condoning no use of modulus signs and absence of \(\ldots + c\)A1 [8]
**(i)**

**Either**

Substitute $x = -1$ and evaluate | M1 |
Obtain 0 and conclude $x + 1$ is a factor | A1 |

**Or**

Divide by $x + 1$ and obtain a constant remainder | M1 |
Obtain remainder = 0 and conclude $x + 1$ is a factor | A1 | [2]

**(ii)**

Attempt division, or equivalent, at least as far as quotient $4x^2 + kx$ | M1 |
Obtain complete quotient $4x^2 - 5x - 6$ | A1 |
State form $\frac{A}{x + 1} + \frac{B}{x - 2} + \frac{C}{4x + 3}$ | A1 |
Use relevant method for finding at least one constant | M1 |
Obtain one of $A = -2, B = 1, C = 8$ | A1 |
Obtain all three values | A1 |
Integrate to obtain three terms each involving natural logarithm of linear form | M1 |
Obtain $-2\ln(x + 1) + \ln(x - 2) + 2\ln(4x + 3)$, condoning no use of modulus signs and absence of $\ldots + c$ | A1 | [8]
7 (i) Show that ( $x + 1$ ) is a factor of $4 x ^ { 3 } - x ^ { 2 } - 11 x - 6$.\\
(ii) Find $\int \frac { 4 x ^ { 2 } + 9 x - 1 } { 4 x ^ { 3 } - x ^ { 2 } - 11 x - 6 } \mathrm {~d} x$.

\hfill \mbox{\textit{CAIE P3 2015 Q7 [10]}}